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Vesnalui [34]
3 years ago
13

A box is being pulled to the right. What is the magnitude of the Kinect frictional force?

Physics
2 answers:
Anna35 [415]3 years ago
3 0
The answer to this question is A - 25 N
natima [27]3 years ago
3 0

The so-called "force" of friction always acts exactly opposite to the direction in which an object is moving.  So for this question, since the box is moving to the right, the "force" of friction is acting toward the left.

There's not enough information given in the question to determine its magnitude.

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Yor older sister drove 500 miles to college one way in ten hours. what is her average velocity?
Lubov Fominskaja [6]
Average velocity is calculated as the division of displacement and change in time so the answer would be 804 km/36000 s=0.02 m/s
8 0
3 years ago
What force does the water exert (in addition to that due to atmospheric pressure) on a submarine window of radius 44.0 cm at a d
Butoxors [25]
Calculate the pressure due to sea water as density*depth.
That is, 
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa

Atmospheric pressure is  101.3 kPa
Total pressure is  94423 + 101.3 = 94524 kPa (approx)

The area of the window is π(0.44 m)^2 = 0.6082 m^2

The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
3 0
4 years ago
Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we
jeka57 [31]

(a) 4.14 rad/s^2

The relationship beween centripetal acceleration and angular speed is

a=\omega^2 r

where

\omega is the angular speed

r is the radius of the circular path

Here we gave

a = 9g = 88.2 m/s^2 is the centripetal acceleration

r = 5.15 m is the radius

Solving for \omega, we find:

\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

v=\omega r

where

v is the linear speed

\omega is the angular speed

r is the radius of the circular path

In this problem we have

\omega=4.14 rad/s

r = 5.15 m

Solving the equation for v, we find

v=(4.14 rad/s)(5.15 m)=21.3 m/s

7 0
3 years ago
Read 2 more answers
A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.52 radians with the
vovangra [49]

Answer:

a = 8.951 m/s²

Explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

acceleration = ?

using

F +  f = m a

mg sin θ +  μk mg cos θ = m a

a = g sin θ  + μk g cos θ

a = 9.8 x  sin 0.52 + 0.48 x 9.8 x  cos 0.52

a = 4.869 + 4.082

a = 8.951 m/s²

the magnitude of acceleration is a = 8.951 m/s²

8 0
3 years ago
The handle of a pressure cooker is covered with plastic.why?
Ilya [14]

Answer: handle of pressure cooker is covered with thick plastic. ... Plastic is a bad conductor of heat. The pressure cooker is made of metal which can conduct heat. Thus, to protect us from burns, the handles of a pressure cooker is made of plastic

Please mark me as Brainliest

Thank you

Explanation:

8 0
4 years ago
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