Answer:
(A) 10132.5Pa
(B)531kJ of energy
Explanation:
This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.
Given
m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³
P1 = 101325Pa. M = 102.03g/mol
P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa
(B) Energy is transfered by the r134a in the form of thw work done in in expansion
W = nRTIn(V2/V1)
n = m / M = 10000/102.03 = 98.01mols
W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)
= 531kJ.
It expands and pushes the crack further aprt
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (starting speed)
Change in speed = (60 km/hr) - (50 km/hr) = 10 km/hr
Time for the change = 12 sec
Acceleration = (10 km/hr) / (12 sec)
Acceleration = 0.8333 km/hr-sec
Convert to a unit that we can understand:
Acceleration = (0.8333 km/hr-sec)x(1000 m/km)x(hr/3600sec)
Acceleration = (833.3 / 3600) (m-hr / hr-sec²)
Acceleration = (833.3 / 3600) (m/s²)
<em>Acceleration = 0.231 m/s² </em> or 0.833 km/hr-sec²
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