The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.
We can calculate the average force with the average acceleration as follows:
(1)
Where:
- m: is the mass of water = 0.60 kg
: is the average acceleration
The <em>average acceleration</em> is given by the change of velocity in an interval of time
(2)
Where:
: is the initial velocity = 0 (the squid is at rest)
: is the final velocity = 15.0 m/s
: is the initial time = 0
: is the final time = 0.15 s
Now we can find the <em>average force</em> after entering equation (2) into (1)
Therefore, the average force on the squid during the propulsion is 60 N.
Find more about average force here:
I hope it helps you!
Answer:
The acceleration will become 9/2 times.
a' =9/2 a
Explanation:
We know that acceleration of a particle when it is moving in the circular path is given as

r=radius
ω= angular speed
If the speed ω '= 3 ω
If the radius ,
The final acceleration =a'






Therefore the acceleration will become 9/2 times.
Answer:
Part a)

Part b)

Part c)

Part d)
Displacement for entire trip = 0
Part e)
Average velocity for entire trip will be zero
Explanation:
Part a)
Displacement after t = 2.4 hours is the straight line distance between initial and final positions
so we have

Part b)
Average velocity is defined as



Part c)
During his return journey the displacement will be same


so average velocity is defined as


Part d)
Displacement for entire trip = 0
as initial and final position will be same
Part e)
Average velocity for entire trip will be zero
C) Some of the light's energy is absorbed by the wall, and some of the light is reflected in different directions
Answer:
is this like a book orsomthing
Explanation: