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3 years ago

What common laboratory measuring device will we likely always use in experiments that measure enthalpy changes?

Physics

1 answer:

adelina 88 [10]3 years ago

5 0

The most common measuring device to be used in measuring enthalpy changes is the thermometer.

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1 If you measured the distance travelled by a snail in

Fittoniya [83]

The answer is m/s hope it helps

3 0

2 years ago

Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci

sweet [91]

Answer:

Don't know sorry..................

4 0

3 years ago

Quentin is playing baseball and is batting. He swings and hits the ball sending it flying to the outfield. Which is greater- the

Bess [88]

Answer:

The force of the ball on the bat is same as the force of the bat on the ball.

Explanation:

A bat hits the ball and the ball moves to the out filed.

According to the Newton's third law, for every action there is an equal and opposite reaction.

The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.

As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.

So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.

5 0

3 years ago

If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is

Anvisha [2.4K]

Question :-

If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

$\bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\$

Where ,

V denotes to Final Velocity .
U denotes to Initial Velocity .
T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

$\dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\$

$\longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\$

$\longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\$

$\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}$

Hence :-

Acceleration = 0.70 m/s² .

$\underline {\rule {210pt} {4pt}}$

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7 0

2 years ago

Read 2 more answers

Warm air aloft is normally higher pressure relative to colder air aloft, which is normally of lower pressure (at equivalent alti

Allisa [31]

Answer:

the statement given is False.

Explanation:

The pressure is defined by

P = F / A

The force of the air is its weight,

P = W_air / A

The weight of an air column on us depends on the energy of the molecules that is related to the temperature

E = 3/2 K T

When the air is warmer it has more energy so the molecules can move more distance and therefore the average density of the gas decreases, as the density decreases, the weight of the column on us also decreases, therefore the pressure low.

The correct statement is: When the air is hotter it has less pressure than when the air is cold.

It is summary the statement given is False

6 0

4 years ago