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kirza4 [7]
3 years ago
13

Two wheels having the same radius and mass rotate at the same angular velocity ((Figure 1) ). One wheel is made with spokes so n

early all the mass is at the rim. The other is a solid disk.How do their rotational kinetic energies compare?A. The wheel with spokes has higher KE, but not twice as high.B. They are nearly the same.C. The solid wheel has higher KE, but not twice as high.D. The solid wheel has about twice the KE.E. The wheel with spokes has about twice the KE.
Physics
2 answers:
liubo4ka [24]3 years ago
6 0

Answer:

E. The wheel with spokes has about twice the KE.

See explanation in: https://quizlet.com/100717504/physics-8-mc-flash-cards/

In-s [12.5K]3 years ago
6 0

Answer:

Explanation:

We have to consider how the location of the mass affects the moment of inertia.

For a solid cylinder, I = mR²

For a hollow cylinder, I = 1/2mR²

Where

I ist the moment of inertia,

m is their masses,

R is the radius of rotation.

Since they have the same mass and radius, it can be seen that a hollow cylinder has twice the moment of inertia as a solid cylinder of the same mass and radius.

We know that the rotational kinetic energy is proportional to the moment of inertia. From;

Rotational KE = 1/2IW²

Where W is the angular speed.

so that at the same angular speed, the wheel with the spokes will have about double the kinetic energy as the solid cylinder. Take note that some of the mass is in the spokes so the moment of inertia is not exactly double.

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jonny [76]

To solve this problem it is necessary to apply the concepts related to the relationship between tangential velocity and centripetal velocity, as well as the kinematic equations of angular motion. By definition we know that the direction of centripetal acceleration is perpendicular to the direction of tangential velocity, therefore:

a_c= \frac{v^2}{r}=r\omega^2

Where,

V = the linear speed

r = Radius

\omega = Angular speed

The angular speed is given by

\omega =6500\frac{rev}{min}(\frac{2\pi rad}{1 rev})(\frac{1 min}{60s})

\omega = 680.6784 rad/s.

Replacing at our first equation we have that the centripetal acceleration would be

a_c = r\omega^2

a_c = (0.0750)(680.6784)^2

a_c = 34 749.23 m/s^2

To transform it into multiples of the earth's gravity which is given as 9.8m / s the equivalent of 1g.

a_c =34749.23 \frac{m}{s^2} (1\frac{g}{9.8m/s^2})

a_c = 3545.84g

PART B) Now the linear speed would be subject to:

v = \omega r

v= (680.6784)(0.0750)

v=51.05 m/s

Therefore the linear speed of a point on its edge is 51.05m/s

8 0
3 years ago
which type of relationship exists when a certain type of trees roots need a fungus present in order to grow normally
Afina-wow [57]
Judging on the fact that this is middle school physics, I would say that it is a beneficial relationship. 
5 0
3 years ago
Read 2 more answers
A box is pushed toward the right across a classroom floor.The force of friction on the box is directed toward the
noname [10]
Left. Opposite of the direction the box is pushed.
4 0
3 years ago
A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of
Alchen [17]

Answer:

The speed of the block when it is 5.00 m from the top of the incline is 3.04 m/s

Explanation:

given information:

s = 7.80 m

v = 3.8 m/s

if s = 5 m, v?

first we have to find the acceleration of the block using the following equation:

v² = v₀² + 2as, v₀²  = 0 thus

3.8² = 2 a 7.8

a = 0.93

so, if s = 5m the final speed is

v² = 2 (0.93) (5)

   = 9.26

v = √9.26

  = 3.04 m/s

5 0
3 years ago
A ray of red light in air is incident at an angle of 30. on a
Vlad [161]

Answer:

20 degrees.

Explanation:

From Snell’s law of refraction:

sinθ1•n1 = sinθ2•n2

where θ1 is the incidence angle, θ2 is the refraction angle, n1 is the refraction index of light in medium1, and n2 is the refraction index for virgin olive oil. The incidence angle of the red light is θ1 = 30 degrees.

The red light is in air as medium1, so n1 (air) = 1.00029

So, to find θ2, the refracted angle:

sinθ1•1.00029 = sinθ2•1.464

sin(30)•1.00029 / 1.464 = sinθ2

0.5•1.00029 / 1.464 = sinθ2

sinθ2 = 0.3416291

θ2 = arcsin(0.3416291)

θ2 = 19.976 degrees

To the nearest degree,

θ2 = 20 degrees.

8 0
3 years ago
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