<span>The magnitude of the gravitational force between two bodies is the product of their masses divided by the square of the distance between them. So we have F = M1*M2 / r^2. M1 = 7.503 * 10e24 and M2 = 2.703 * 10e22 and r= 2.803 * 10e8; r^2 = 5.606 *10e16. So we have 7.503 *2.703 *10^(24+22) = 20.280 * 10^(46). Then we divide our answer by 5.606 * 10e16 which is the distance ; then we have 3.6175 * 10 e (46- 16) = 3.6175 * 10e30.
To find the acceleration we use Newton's second law F = ma. F is 3.6175 * 10e30 and M is 7.503 * 10e24 so a = F/M and then we have 3.6175/7.503 * 10e (30-24) = 0.48 * 10e6.
Similarly for moon, we have a = 3.6715/2.703 * 10e(30-22). = 1.358 * 10e8</span>
Answer:
1) Skid
2)<u> </u>Rocking
3) Oversteer situation
4) Controlled breaking
5) Overdriving headlights
6) Hydroplaning
7) Understeer situation
Explanation:
1) A <u>skid</u> results when a vehicle loses part or all of its grip on the road
2)<u> Rocking</u> is a technique that can be applied when trying to move your vehicle out of deep snow
3) The action of vehicle's rear end sliding out to a side is called an <u>oversteer situation</u>
4) <u>Controlled breaking</u> is a technique of reducing your speed as quick as possible while maintaining control of your vehicle
5) Driving at a speed where the stopping distance of your vehicle is longer than the distance you can see with your headlights is called <u>overdriving headlights</u>
6) <u>Hydroplaning</u> occurs when a tire loses road surface contact and rises on top of water
7) It is an <u>understeer situation</u> when your front tires begin to plow and your vehicle is not responding or not responding as quickly as it should, to a steering point
Answer:
4V
Explanation:
First, we calculate the total resistance to the given battery cell of emf 5V. The total resistance is the sum of all the resistance in the cell i.e.
Total resistance = 2Ω + 8Ω = 10Ω
Using ohms law equation to calculate the current passing through the battery cell:
V = IR
Where; V = voltage, I = current, R = resistance
5V = I × 10Ω
I = 5/10
I = 0.5A
Terminal voltage is calculated by the us of the following equation:
V=emf−IR
Where; R is internal resistance
V = 5 - (0.5 × 2)
V = 5 - 1
V = 4V
Therefore, the potential difference across the terminals of the battery cell is 4V
Potential energy = mgh
So, energy gained
= mgh
= 70kg × (9.8m/s²) × 1000m
= 686000 kgm²/s²
= 686000 J
