It is B) Wavelength, because it measures the "length" between "waves", therefore, wavelength.
Explanation:
From a new Moon, when the Moon is situated in orbit between the Earth and the Sun with its dark side in shadow facing towards us, the amount of lunar surface visible from the Earth increases through waxing crescent, first quarter and waxing gibbous phases until it becomes full.
Or
The new moon is the phase that is invisible to us here on Earth because the moon is between the earth and the sun, and its illuminated side is facing away from us. A solar eclipse occurs when the moon moves in front of the sun, blocking it from our view on Earth.
Answer:
Half
Explanation:
Given that:
- radial distance of satellite from the earth,
Now, if the satellite is moved to a distance 
<u>We have the mathematical expression for the potential energy fue to gravitational field as:</u>
...................(1)
where:
M = mass of earth
m = mass of satellite
R = radial distance of satellite
<u>Now from eq. (1) initially we have:</u>
<u>after the satellite is moved, we have:</u>
which is half of the initial condition.
<h3>
Answer:</h3>
209.236 kg · m/s
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Physics</u>
<u>Momentum</u>
Momentum Formula: P = mv
- P is momentum (in kg · m/s)
- m is mass (in kg)
- v is velocity (in m/s)
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
m₁ = 87.2 kg
v₁ = 2.87 m/s
m₂ = 0.0520 kg
v₂ = 789 m/s
<u>Step 2: Find Momentums</u>
<em>Football Player</em>
- Substitute [MF]: P = (87.2 kg)(2.87 m/s)
- Multiply: P = 250.264 kg · m/s
<em>Bullet</em>
- Substitute [MF]: P = (0.0520 kg)(789 m/s)
- Multiply: P = 41.028 kg · m/s
<u>Step 3: Find difference</u>
- Define equation: P₁ - P₂
- Substitute: 250.264 kg · m/s - 41.028 kg · m/s
- Subtract: 209.236 kg · m/s
Answer:
Explanation:
Given,
mass of the object,m = 0.30 Kg
initial speed, v_i = 3 m/s
time of collision = 0.20 s
final speed, v_f = -4 m/s
Impulse = change in momentum
Hence, impulse of the object is equal to
