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Svetradugi [14.3K]

3 years ago

11

In an airless test-facility, a bullet is fired from a gun horizontally, at a height of 1 m. at the same time, another identical

bullet is dropped from the same height. what is true about the acceleration of the two bullets while they are in flight?

1 answer:

nydimaria [60]3 years ago

8 0

The acceleration is the same for both the bullet fired and dropped

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A cyclist travelled 32 kilometers for both the 1st and 2nd hours. He took a 30 minute break to eat his lunch. He then travelled

Reika [66]

Answer:

The cyclist's average speed is 13.43 $\frac{km}{h}$

Explanation:

Speed is a quantity that expresses the relationship between the space traveled by an object and the time used for it. That is, speed is the magnitude that expresses the variation in position of an object and as a function of time, which would be the same as saying that it is the distance traveled by an object in the unit of time.

Average speed relates the change in position to the time taken to effect that change:

$speed=\frac{change in position}{time} =\frac{distance}{time}$

In this case:

total distance traveled= 32 km + 15 km= 47 km
total time= 3 hours that the cyclist travels + 30 minutes of rest = 3 hours + 0.5 hours (being 60 minutes equal to 1 hour, then 30 minutes equals 0.5 hours) = 3.5 hours

Replacing:

$speed=\frac{47 km}{3.5 h}$

and solving, you get:

speed= 13.43 $\frac{km}{h}$

<u><em>The cyclist's average speed is 13.43 </em></u> $\frac{km}{h}$ <u><em></em></u>

3 0

3 years ago

11. Newton's Third Law of Motion relates to action and reaction. Which of the following scenarios accurately names the

hoa [83]

Answer:

b

Explanation:

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3 years ago

A 55 kg pole vaulter falls from rest from a height of 5.4 m onto a foam rubber pad. The pole vaulter comes to rest 0.24 s after

AnnZ [28]

Answer:

a) 10.3 m/s

b) 566 N

Explanation:

$v {}^{2} = {u}^{2} + 2as \\ v {}^{2} = 0 {}^{2} + 2(9.81)(5.4) \\ v = 10.3 \: ms {}^{ - 1}$

$force \: = \frac{d(mv)}{dt} \\ = 55(10.293) \\ = 566 \: newtons$

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3 years ago

A swimmer does 3560 j of work in 55 s what is the swimmers power output?

ankoles [38]

Explanation:

<em>Here </em><em>it </em><em>is </em><em>given </em>

<em>Work </em><em>(</em><em>W) </em><em> </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em> </em><em>J</em>

<em>Time </em><em>(</em><em>t) </em><em> </em><em>=</em><em> </em><em>5</em><em>5</em><em> </em><em>sec</em>

<em>power </em><em>(</em><em>P) </em><em> </em><em>=</em><em> </em><em>?</em>

<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>

<em> $p = \frac{w}{t}$ </em>

<em>P </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em>/</em><em>5</em><em>5</em>

<em>P </em><em>=</em><em> </em><em>6</em><em>4</em><em>.</em><em>7</em><em>3</em><em> </em><em>watt</em>

8 0

3 years ago

A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too

maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $90\times 1.989\times 10^{30}\ kg$

$R_{f}$ = 10000+100 m

$R_{sb}$ = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

$\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2$

The acceleration is 2352645198509.9604 m/s²

4 0

3 years ago