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gregori [183]
3 years ago
14

A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.202

m down the incline in 2.00 s. The 0.200 kg block is replaced by a 0.400 kg block. If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?
Physics
1 answer:
love history [14]3 years ago
4 0

Answer: The block of 0.4 Kg travel the same distance that the block of

0.2 Kg

Explanation: Considering the second newton law, we have the following

F= m*a

F= P*sin (θ) where θ is the angle for the incline

so mg sin (θ)= m*a

a=g sin(θ)

both block have the same acceleration in the inclined plane so travel the same distance independent of its mass.

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