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Inga [223]
3 years ago
6

Average distance of 160.0 cm. Its average time was 5.74 seconds. What is its average speed?

Physics
1 answer:
Gre4nikov [31]3 years ago
5 0
Your answer is .279m/s
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We're millions of miles away from mars
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3 years ago
A particle P with speed 140 m s–1begins to decelerate uniformly at a certain instant while another particle Q starts from rest 6
Natasha2012 [34]

Answer:

i) The motion of both particles are shown on the same speed-time curve included

ii) Approximately 19.5 seconds

Explanation:

We are given that;

Initial velocity of particle, P = 140 m/s

Start time of particle P = 6 s before start time of particle Q

Position of particle Q when velocity is 25 m/s = 125 m

Therefore, from the equation of motion, we have for particle Q;

v² = u² + 2·a·s

Where:

v = Final velocity = 25 m/s

u = Initial velocity = 0 m/s

a = Acceleration

s = Distance covered = 125 m

Therefore;

25² = 0² + 2×a×125

Which gives a = 25²/(2×125) = 2.5 m/s²

The time taken for particle Q to reach 125 m is found from the relation;

s = u·t + 1/2·a·t²

Where:

t = Time of journey

Therefore;

125 = 0×t + 1/2×2.5×t²

Which gives 125 = 1.25 × t²

Hence, t² = 125/1.25 = 100

t = √(100) = 10 s

The equation for particle Q is v = 0 + 2.5×t

Hence, since particle P starts deceleration 6 seconds before the commencement of motion of particle Q, the amount of seconds after the commencement of deceleration of the first particle P that it takes for particle P to come to rest is found as follows;

Hence, at t = 6 + 10 = 16 seconds particle P speed = 25 m/s

From the equation of motion, for particle P (decelerating) we have

v = u - a·t

Where:

v = 25 m/s

u = 140 m/s

t = 16 s

Hence, 25 = 140 - a×16

∴ 16·a = 140 - 25 = 115

a = 115/16 = 7.1875 m/s²

Therefore, the time it takes before particle P comes to rest is found from the same equation of motion, where v = 0 as follows;

v = u - a·t

0 = 140 - 7.1875 × t

∴7.1875·t = 140

t = 140/7.1875 = 19.48 s ≈ 19.5 seconds.

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3 years ago
A 20 MHz carrier is frequency modulated by a sinusoidal signal such that the maximum frequency deviation is 100kHz. Calculate th
Ivan

Answer:

Idk

Explanation:

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3 years ago
Learning Goal: To understand the concepts explaining the operation of transformers.
Alex

Answer:

Part a)

ZERO

Part b)

N = 10 turns

Explanation:

Part a)

As we know that transformer is used to change the input voltage into required output voltage

Here this input and output is considered only when it will change with time as the whole concept is based upon Faraday's law where we need to change the flux with time.

So if we have input Source is DC source then output voltage will be zero as there is no flux change

Part b)

As we know by the principle of transformer

\frac{V_1}{V_2} = \frac{N_1}{N_2}

\frac{500}{25} = \frac{200}{N_2}

N_2 = 10

so total number of turns in secondary coil must be 10

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3 years ago
A standard light bulb emits light rays in _________ directions.
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Omni-directional. It means all directional.
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