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3 years ago

Average distance of 160.0 cm. Its average time was 5.74 seconds. What is its average speed?

Physics

1 answer:

Gre4nikov [31]3 years ago

5 0

Your answer is .279m/s

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The speed of light can be measured by;

Bezzdna [24]

Answer:

it's the distance between objects in space

Explanation: Light travels super fast; but it still takes a long time to travel between objects in space. This is because distances between objects in space are enormous.

And can i please receive a brainliest and have a good day

4 0

2 years ago

Uranium-235 decays to thorium-231 with a half-life of 700 million years. When a rock was formed, it contained 6400 million urani

Dahasolnce [82]

Answer:

proof in explanation

Explanation:

First, we will calculate the number of half-lives:

$n = \frac{t}{t_{1/2}}$

where,

n = no. of half-lives = ?

t = total time passed = 2100 million years

$t_{1/2}$ = half-life = 700 million years

Therefore,

$n = \frac{2100\ million\ years}{700\ million\ years}\\\\n = 3$

Now, we will calculate the number of uranium nuclei left ( $n_u$ ):

$n_u = \frac{1}{2^{n} }(total\ nuclei)\\\\n_u = \frac{1}{2^{3} }(6400\ million)\\\\n_u = \frac{1}{8}(6400\ million)\\\\n_u = 800\ million$

and the rest of the uranium nuclei will become thorium nuclei ( $u_{th}$ )

$n_{th} = total\ nuclei - n_u\\n_{th} = 6400\ million-800\ million\\n_{th} = 5600\ million$

dividing both:

$\frac{n_{th}}{n_u}=\frac{5600\ million}{800\ million} \\\\n_{th} = 7n_u$

<u>Hence, it is proven that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.</u>

6 0

2 years ago

"Force" can be defined as a push or a<br> O pull<br> O grab

Nady [450]

Answer:

pull

is your answer please give me some thanks

4 0

2 years ago

Read 2 more answers

A bowling ball moving with a velocity of 5V to the right collides elastically with a beach ball moving at a velocity 2V to the l

katen-ka-za [31]

Answer:

$v'_2=3V$

Explanation:

From the question we are told that:

Bowling ball Speed $v_1=5 m/s$

Beach ball Speed $v_2=2 m/s$

Let The Mass be equal i.e

$M_1=M_2$

Therefore

Generally the equation for Velocity of beach ball after collision $v'_2$ is mathematically given by

Since Velocity is Vector Quantity

Therefore

$v'_2=v_1-v_2$

$v'_2=5-2$

$v'_2=3V$

3 0

3 years ago

2. A hanging wind-chime on a calm day would have kinetic or potential energy?

rjkz [21]

Answer:

it would have potential energy

7 0

3 years ago