I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.
1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.
(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2
)+(10x)+(-3x)+(-15)=2
+7x-15
(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2
)+(-10x)+(-3x)+(15)=2
-13x+15
Your answer is 2
+7x-15 or 2
-13x+15. Does that answer your question?
9514 1404 393
Answer:
WX = 33
(x, y) = (2, 10)
Step-by-step explanation:
The hash marks tell you WX is a midline, so has the measure of the average of the two bases.
WX = (PQ +SR)/2 = (27 +39)/2 = 66/2
WX = 33
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The hash marks also tell you ...
PW = WS
y +4x = 18 . . . . . . substitute the given expressions
and also
QX = XR
2y +x = 22 . . . . . substitute the given expressions
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If you solve the first equation for y, you get ...
y = 18 -4x
Substituting that into the second equation gives ...
2(18-4x) +x = 22
36 -7x = 22 . . . . . . . simplify
14 = 7x . . . . . . . . . . . add 7x-22 to both sides
2 = x . . . . . . . . . . . . divide by 7
y = 18 -4(2) = 10 . . . find y using the above relation
The values of x and y are 2 and 10, respectively.
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My favorite "quick and dirty" way to solve a set of linear equations is using a graphing calculator. It works well for integer solutions.
Answer:
7.)
m<1 = 141
m<2= 39
m<3 = 141
8.)
m<1 = 17
m<2 = 73
m<3 = 107
9.)
m<1 = 101
m<2 = 33
m<3 = 71
Step-by-step explanation:
use the postulates and theorems your teacher gave you.
Also you need some logic
