Given sides of length 300 mm or 190 mm, you can form 4 different triangles:
- equilateral with sides 190 mm
- equilateral with sides 300 mm
- isosceles with two sides 190 mm and one side 300 mm
- isosceles with two sides 300 mm and one side 190 mm
The triangle inequality requires the sum of the lengths of any two sides be not less than the length of the third side. Since 2×190 > 300, you can mix and match these side lengths any way you want. With three sides and 2 choices for each, there are only a limited number of possibilities.
In the above, we have not listed ones that are simply rotations or reflections of a congruent triangle. (A 190-190-300 triangle looks the same as a 190-300-190 triangle, for example.)
It is 4 i am not gonna lie
It would be X=3 because 3 multiplied by 1 equals 3 and you get 3 over 21. that simplifies to 1 over 7.
Answer:
240 houses
Step-by-step explanation:
Given that:
Number of streets = 4
Length of each street = 3/4 miles long
Street is divided into lots with one house built per lot
1 mile = 5289 feets
3/4 miles = (3/4) * 5280 = 3960 feets
Hence, street is 3960 feets long
Since each lot must have at least 65 feet frontage along the street:
Number of lots per street :
Length of street / frontage length
3960 ft / 65 ft = 60.92
Hence, maximum number of lots per street = 60 lots per street
Maximum number of houses in New neighborhoods :
Number of lots per street × number of streets
= 60 × 4
= 240 houses
Answer:
-36+-8=-44
Step-by-step explanation:
