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Fudgin [204]
3 years ago
15

How much total energy is dissipated in 10. seconds

Physics
2 answers:
noname [10]3 years ago
7 0

Answer : Total energy dissipated is 10 J

Explanation :

It is given that,

Time. t = 10 s

Resistance of the resistors, R = 4-ohm

Current, I = 0.5 A

Power used is given by :

P=\dfrac{E}{t}

Where

E is the energy dissipated.

So, E = P t.............(1)

Since, P=I^2R

So equation (1) becomes :

E=I^2Rt

E=(0.5\ A)^2\times 4\Omega \times 10\ s

E=10\ J

So, the correct option is (3)

Hence, this is the required solution.

irinina [24]3 years ago
5 0

Answer:

3) 10 J

Explanation:

Electrical energy dissipated is given as

U = i^2 R T

here we know that

i = electrical current = 0.50 A

R = 4 ohm

T = 10 s

so we have electrical energy given as

U = (0.50)^2(4)(10)

U = 10 J

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The answer is no. If you are dealing with a conservative force and the object begins and ends at the same potential then the work is zero, regardless of the distance travelled. This can be shown using the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.

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3 years ago
How does the intensity of a sound wave change if the distance from the
Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

I=\dfrac{P}{A}

P is power

A is area

I=\dfrac{P}{4\pi r^2}

or

I\propto \dfrac{1}{r^2}, r is distance from the source

If the distance from the  source is increased by a factor of 4, r' = 4r

So,

I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}

So, the new intensity decreases by a factor of 16.

8 0
3 years ago
The second hand on a clock is 3.00 cm long. What is the speed of the outermost tip of that second hand
Gnom [1K]

In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of

(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s

4 0
3 years ago
(100 POINTS!!) Short answer about how acceleration is dependent on the speed and direction of an object!!!! please help!!!!!
zhuklara [117]

Answer:

The acceleration of the object is dependent upon this velocity change and is in the same direction as this velocity change. The acceleration of the object is in the same direction as the velocity change vector; the acceleration is directed towards point C as well - the center of the circle.

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Explanation:

8 0
3 years ago
Read 2 more answers
A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms
babymother [125]

Answer:

The intensity of the EM wave is 5.729 W/m²

The rms value of the electric field is 46.452 V/m

Explanation:

Given;

power of the electromagnetic wave, P = 1800 W

The intensity of light is given by;

I = P / A

Where;

A is the surface area of the sphere = 4πr²

A is the surface area of the sphere = 4π(5)²

A is the surface area of the sphere = 314.2 m²

The intensity is calculated as;

I = P / A

I = (1800) / (314.2)

I = 5.729 W/m²

The rms value of the electric field is given by;

E_{rms} = \sqrt{\frac{I}{c \epsilon _o}}\\\\E_{rms} = \sqrt{\frac{5.729}{(3*10^8)( 8.85*10^{-12})}}\\\\E_{rms} = 46.452 \ V/m

8 0
3 years ago
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