Question

How much total energy is dissipated in 10. seconds

Answer 1

Answer : Total energy dissipated is 10 J

Explanation :

It is given that,

Time. t = 10 s

Resistance of the resistors, R = 4-ohm

Current, I = 0.5 A

Power used is given by :

$P=\dfrac{E}{t}$

Where

E is the energy dissipated.

So, E = P t.............(1)

Since, $P=I^2R$

So equation (1) becomes :

$E=I^2Rt$

$E=(0.5\ A)^2\times 4\Omega \times 10\ s$

$E=10\ J$

So, the correct option is (3)

Hence, this is the required solution.

Answer 2

Answer:

3) 10 J

Explanation:

Electrical energy dissipated is given as

$U = i^2 R T$

here we know that

i = electrical current = 0.50 A

R = 4 ohm

T = 10 s

so we have electrical energy given as

$U = (0.50)^2(4)(10)$

$U = 10 J$