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astraxan [27]
3 years ago
14

Russell bradley carried 207 kg of bricks 3.65 m up a ladder. If the amount of work required to perform that task is used to comp

ress a gas at a constant pressure of 1.8 X 10^6 Pa, what is the change in volume of the gas?
Physics
2 answers:
MrRa [10]3 years ago
8 0

Answer:

Explanation:

Work done in carrying bricks

mgh

= 207 x 9.8 x 3.65

-= 7404.4 J

Work done in compressing gas

PΔV

Pressure x change in volume

1.8 x 10⁶ ΔV = 7404.4

ΔV  = 7404.4  / 1.8 x 10⁶m³

= 4113.33 x 10⁻⁶ m³

= 4113.33 cc

vodka [1.7K]3 years ago
6 0

Answer:

dV=4.1136\times 10^{-4}\ m^3

Explanation:

Given:

  • Mass of the bricks carried, m=207\ kg
  • height of displacement, h=3.65\ m
  • Constant pressure of the gas, P=1.8\times 10^6\ Pa

<u>Now the work done to displace the brick along the length of the ladder:</u>

W=(m.g)\times h

W=(207\times 9.8)\times 3.65

W=740.439\ J

<u>As we know that the work done in compressing the gas at constant pressure is given as:</u>

W=P.dV

where:

dV= change in volume of the gas

740.439=1.8\times 10^6\times dV

dV=4.1136\times 10^{-4}\ m^3

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