Question

Russell bradley carried 207 kg of bricks 3.65 m up a ladder. If the amount of work required to perform that task is used to compress a gas at a constant pressure of 1.8 X 10^6 Pa, what is the change in volume of the gas?

Answer 1

Answer:

Explanation:

Work done in carrying bricks

mgh

= 207 x 9.8 x 3.65

-= 7404.4 J

Work done in compressing gas

PΔV

Pressure x change in volume

1.8 x 10⁶ ΔV = 7404.4

ΔV  = 7404.4  / 1.8 x 10⁶m³

= 4113.33 x 10⁻⁶ m³

= 4113.33 cc

Answer 2

Answer:

$dV=4.1136\times 10^{-4}\ m^3$

Explanation:

Given:

• Mass of the bricks carried, $m=207\ kg$

• height of displacement, $h=3.65\ m$

• Constant pressure of the gas, $P=1.8\times 10^6\ Pa$

Now the work done to displace the brick along the length of the ladder:

$W=(m.g)\times h$

$W=(207\times 9.8)\times 3.65$

$W=740.439\ J$

As we know that the work done in compressing the gas at constant pressure is given as:

$W=P.dV$

where:

$dV=$ change in volume of the gas

$740.439=1.8\times 10^6\times dV$

$dV=4.1136\times 10^{-4}\ m^3$