Answer:
V = 4.48m/s a = 1.57m/s²
Explanation:
ω₀ = 16rad/s
α₀ = 5.6rad/s²
r = 280mm = 0.28m
a = ?
v = ?
Angular velocity (ω₀) = velocity of acceleration / length of path
ω₀ = v / r
V = ω₀ * r
V = 16 * 0.28
V = 4.48m/s
Acceleration = ?
Angular acceleration α₀ = angular velocity (ω) / time take (t)
α₀ = ω / t .... equation i
But acceleration (a) = velocity (v) / time (t)
a = v / t
t = v / a
Put t = v / a into equation i
α₀ = ω / (v / a)
α₀ = ω * a / v
α * v = ω * a
a = (α * v) / ω
a = (5.6 * 4.48) / 16
a = 1.568m/s²
a = 1.57m/s²
The South Pole of a magnet attracts Iron
The final speed of the cart and the bag is 2.2 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the bag and the cart must be conserved before and after the collision.
Mathematically:
where:
is the mass of the bag of rice
is the initial velocity of the bag
is the mass of the cart
is the initial velocity of the cart (at rest)
is the final combined velocity of the bag and the cart
Re-arranging the equation and solving for v, we find:
Learn more about momentum here:
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I think the answer is B because I did this before
