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salantis [7]
3 years ago
14

As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -

1.4 V during one revolution. Assuming the shuttle is a conducting sphere of radius 15 m, estimate the amount of charge it collects.
Physics
1 answer:
postnew [5]3 years ago
4 0

Answer:

-2.3 × 10^-9 Coulombs(C).

Explanation:

So, we are given the following data or information or parameters that is going to help us to solve the problem effectively and efficiently;

=> " the shuttle's potential is typically changed by -1.4 V during one revolution. "

=> " Assuming the shuttle is a conducting sphere of radius 15 m".

So, in order to estimate the value for the charge we will be making use of the equation below:

Charge, C =( radius × voltage or potential difference) ÷ Coulomb's law constant.

Note that the value of Coulomb's law constant = 9 x 10^9 Nm^2 / C^2.

So, charge = { 15 × (- 1.4)} / 9 x 10^9 Nm^2 / C^2.

= -2.3 × 10^-9 Coulombs(C).

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Monochromatic light with wavelength 588 nm is incident on a slit with width 0.0351 mm. The distance from the slit to a screen is
Norma-Jean [14]

Answer:

Explanation:

A. Using

Sinစ= y/ L = 0.013/2.7= 0.00481

စ=0.28°

B.here we use

Alpha= πsinစa/lambda

= π x (0.0351)sin(0.28)/588E-9m

= 9.1*10^-2rad

C.we use

I(စ)/Im= (sin alpha/alpha) ²

So

{= (sin0.091/0.091)²

= 3*10^-4

6 0
4 years ago
A weather balloon is designed to expand to a maximum radius of 24 m at its working altitude, where the air pressure is 0.030 atm
nlexa [21]

Answer:

<em>Radius at liftoff 8.98 m</em>

Explanation:

At the working altitude;

maximum radius = 24 m

air pressure = 0.030 atm

air temperature = 200 K

At liftoff;

temperature = 349 K

pressure = 1 atm

radius = ?

<em>First, we assume balloon is spherical in nature,</em>

<em>and that the working gas obeys the gas laws.</em>

from the radius, we can find the volume of the balloon at working atmosphere.

Volume of a sphere = \frac{4}{3} \pi r^{3}

volume of balloon = \frac{4}{3} x 3.142 x 24^{3} = 57913.34 m^3

using the gas equation,

\frac{P1V1}{T1} = \frac{P2V2}{T2}

<em>The subscript 1 indicates the properties of the gas at working altitude, and the subscript 2 indicates properties of the gas at liftoff.</em>

imputing values, we have

\frac{0.03*57913.34}{200} = \frac{1*V2}{349}

0.03 x 57913.34 x 349 = 200V2

V2 = 606352.67/200 = <em>3031.76 m^3  this is the volume occupied by the gas in the balloon at liftoff.</em>

from the formula volume of a sphere,

V =  \frac{4}{3} \pi r^{3} =  \frac{4}{3} x 3.142 x r^{3} = 3031.76

4.19r^{3}  = 3031.76

r^{3} = 3031.76/4.19  

radius r of the balloon on liftoff = \sqrt[3]{723.57} = <em>8.98 m</em>

4 0
3 years ago
When the course deviation indicator (CDI) needle is centered during an omnireceiver check using a VOR test signal (VOT), the omn
lilavasa [31]

Answer:

0° FROM or 180° TO

Explanation:

A course deviation indicator or the CDI may be defined as an avionics tool or instrument that is used in the aircraft navigation which is used to determine an aircraft's lateral position with relation to a course.

While using the VOT service, we should tune the VOT frequency of the VOR receiver. And with the CDI leveled centered, the omnibearing selector or the OBS should read as 0° with the TO/FROM indicator showing 'FROM'. Else the OBS should read as 180° with the TO/FROM indication showing 'TO.'

4 0
3 years ago
Froghopper insects have a typical mass of around 11.3 mg and can jump to a height of 58.8 cm. The takeoff velocity is achieved a
allochka39001 [22]

Answer:

2874.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{v^2-0^2}{2\times h}\\\Rightarrow v^2=2ah\ m/s

Now H-h = 0.588 - 0.002 = 0.586 m

The final velocity will be the initial velocity

v^2-u^2=2as\\\Rightarrow 0^2-u^2=2gs\\\Rightarrow -2ah=2\times g(H-h)\\\Rightarrow -2a0.002=2\times g0.586\\\Rightarrow a=-\frac{0.586\times -9.81}{0.002}\\\Rightarrow a=2874.33\ m/s^2

Acceleration of the frog is 2874.33 m/s²

6 0
4 years ago
If an object has the the mass of 3kg, calculate the force acting on it.
Verdich [7]
Well first, how do we determine force?

6 0
3 years ago
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