The tension in the first and second rope are; 147 Newton and 98 Newton respectively.
Given the data in the question
- Mass of first block;
![m_1 = 5.0kg](https://tex.z-dn.net/?f=m_1%20%3D%205.0kg)
- Mass of second block,
![m_2 =10kg](https://tex.z-dn.net/?f=m_2%20%3D10kg)
- Tension on first rope;
![T_1 =\ ?](https://tex.z-dn.net/?f=T_1%20%3D%5C%20%3F)
- Tension on second rope;
To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:
![F = m\ *\ a](https://tex.z-dn.net/?f=F%20%3D%20m%5C%20%2A%5C%20a)
Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity
)
For the First Rope
Total mass hanging on it; ![m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg](https://tex.z-dn.net/?f=m_T%20%3D%20m_1%20%2B%20m_2%20%3D%205.0kg%20%2B%2010.0kg%20%3D%2015.0kg)
So Tension of the rope;
![F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N](https://tex.z-dn.net/?f=F%20%3D%20m%5C%20%2A%20%5C%20g%5C%5C%5C%5CF%20%3D%2015.0kg%20%5C%20%2A%209.8m%2Fs%5E2%5C%5C%5C%5CF%20%3D%20147%20kg.m%2Fs%5E2%5C%5C%5C%5CF%20%3D%20147N)
Therefore, the tension in the first rope is 147 Newton
For the Second Rope
Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;
![F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N](https://tex.z-dn.net/?f=F%20%3D%20m%5C%20%2A%20%5C%20g%5C%5C%5C%5CF%20%3D%2010.0kg%20%5C%20%2A%209.8m%2Fs%5E2%5C%5C%5C%5CF%20%3D%2098%20kg.m%2Fs%5E2%5C%5C%5C%5CF%20%3D%2098N)
Therefore, the tension in the second rope is 98 Newton
Learn More, brainly.com/question/18288215
Vas happenin!!
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Hope this helps *smiles*
Answer:
a) ![v=0.999124c](https://tex.z-dn.net/?f=v%3D0.999124c)
b) ![E=7.566*10^{22}](https://tex.z-dn.net/?f=E%3D7.566%2A10%5E%7B22%7D)
c) ![E_a=760 times\ larger](https://tex.z-dn.net/?f=E_a%3D760%20times%5C%20larger)
Explanation:
From the question we are told that
Distance to Betelgeuse ![d_b=430ly](https://tex.z-dn.net/?f=d_b%3D430ly)
Mass of Rocket ![M_r=20000](https://tex.z-dn.net/?f=M_r%3D20000)
Total Time in years traveled ![T_d=36years](https://tex.z-dn.net/?f=T_d%3D36years)
Total energy used by the United States in the year 2000 ![E_{2000}=1.0*10^20](https://tex.z-dn.net/?f=E_%7B2000%7D%3D1.0%2A10%5E20)
Generally the equation of speed of rocket v mathematically given by
![v=\frac{2d}{\triangle t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2d%7D%7B%5Ctriangle%20t%7D)
![v=860ly/ \triangle t](https://tex.z-dn.net/?f=v%3D860ly%2F%20%5Ctriangle%20t)
where
![\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D%5Cfrac%7B%5Ctriangle%20t%27%7D%7B%28%5Csqrt%7B1-860%2F%20%5Ctriangle%20t%29%5E2%7D%7D)
![\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D%5Cfrac%7B36%7D%7B%28%5Csqrt%7B1-860%2F%20%5Ctriangle%20t%29%5E2%7D%7D)
![\triangle t=\sqrt{(860)^2+(36)^2}](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D%5Csqrt%7B%28860%29%5E2%2B%2836%29%5E2%7D)
![\triangle t=860.7532](https://tex.z-dn.net/?f=%5Ctriangle%20t%3D860.7532)
Therefore
![v=\frac{860ly}{ 860.7532}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B860ly%7D%7B%20860.7532%7D)
![v=0.999124c](https://tex.z-dn.net/?f=v%3D0.999124c)
b)
Generally the equation of the energy E required to attain prior speed mathematically given by
![E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%28v%2Fc%29%5E2%7D%20%7D-1%2820000kg%29%283%2A10%5E8m%2Fs%29%5E2)
![E=7.566*10^{22}](https://tex.z-dn.net/?f=E%3D7.566%2A10%5E%7B22%7D)
c)Generally the equation of the energy
required to accelerate the rocket mathematically given by
![E_a=\frac{E}{E_{2000}}](https://tex.z-dn.net/?f=E_a%3D%5Cfrac%7BE%7D%7BE_%7B2000%7D%7D)
![E_a=\frac{7.566*10^{22}}{1.0*10^{20}}](https://tex.z-dn.net/?f=E_a%3D%5Cfrac%7B7.566%2A10%5E%7B22%7D%7D%7B1.0%2A10%5E%7B20%7D%7D)
![E_a=760 times\ larger](https://tex.z-dn.net/?f=E_a%3D760%20times%5C%20larger)
Answer:
astronauts age is 32 years
correct option is e 32 years
Explanation:
given data
travels = 20 light year
stay = 2 year
return = 52 years
to find out
astronauts aged
solution
we know here they stay 2 year so time taken in traveling is
time in traveling = ( 52 -2 ) = 50 year
so it mean 25 year in going and 25 years in return
and distance is given 20 light year
so speed will be
speed = distance / time
speed = 20 / 25 = 0.8 light year
so time is
time = ![\frac{t}{\sqrt{1-v^2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt%7D%7B%5Csqrt%7B1-v%5E2%7D%20%7D)
time = ![\frac{25}{\sqrt{1-0.8^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B%5Csqrt%7B1-0.8%5E2%7D%20%7D)
time = 15 year
so age is 15 + 2 + 15
so astronauts age is 32 years
so correct option is e 32 years
Mantle convection<span> is the slow creeping motion of Earth's solid silicate </span>mantle<span> caused by </span>convection<span> currents carrying heat from the interior of the Earth to the surface.
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