C. Acceleration is the rate of change of velocity. So at the top of the path, while the velocity is zero, the CONSTANT GRAVITATIONAL ACCELERATION is about 10 m/s^2 (9.8)
Answer:
ans 5
Explanation:
hope it's help It seems to me
Answer:
Explanation:
Time dilation formula is
T = T₀ / √ 1-v²/c²
T₀ is time elapsed in moving reference , T time elapsed in stationary reference.
Here T₀ = 1 second
T = 1/√ 1-0.9² = 1/.4358 = 2.3 second
So 2.3 second will pass for each second on moving reference.
The amount of current passing through the point is 1 A
The amount of current passing through the point can be calculated using the formula below.
⇒ Formula:
- Q = i/t......................... Equation 1
⇒ Where:
- Q = Charge
- i = current
- t = time.
⇒ Make "i" the subject of the equation.
- i = Qt....................... Equation 2
From the question,
⇒ Given:
- Q = 1000 millicoulombs = 1 coulombs
- t = 1 seconds. (Assuming the time is 1 seconds)
⇒ Substitute these values into equation 2
Hence, The amount of current passing through the point is 1 A.
Learn more about charges here: brainly.com/question/4158552
With its apparent magnitude
