Answer:
0.0109 m ≈ 10.9 mm
Explanation:
proton speed = 1 * 10^6 m/s
radius in which the proton moves = 20 m
<u>determine the radius of the circle in which an electron would move </u>
we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)
For proton :
Mp*V^2 / rp = qp *VB ∴ rp = Mp*V / qP*B ---------- ( 1 )
For electron:
re = Me*V/ qE * B -------- ( 2 )
Next: take the ratio of equations 1 and 2
re / rp = Me / Mp ( note: qE = qP = 1.6 * 10^-19 C )
∴ re ( radius of the electron orbit )
= ( Me / Mp ) rp
= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20
= ( 5.45 * 10^-4 ) * 20
= 0.0109 m ≈ 10.9 mm
Answer:
See below
Explanation:
Distance = 27 + 13 = 40 km
Displacement = 27 - 13 = 14 km
Answer:
the net force would be 3N in the upward direction since the two forces acting on the left and right of the object cancel out.
Explanation:
We assume
(acceleration is constant. We apply the equation
where s is the distance to stop
. We find the acceleration from this equation
We know the acceleration, thus we find the distance necesssary to stop when initial speed is
The distance between two points on a graph is
Square root of [ (difference in the y-values)² + (difference in the x-values)² ] .
So for these two points, the distance between them is
square root of [ (-5)² + (12)² ] =
square root of [ 25 + 144 ] =
square root of [ 169 ] =
<em>13 .</em>
Yes, the ' 13 ' you typed at the end of the question is the correct answer to it.
