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guapka [62]
3 years ago
8

Unlike a longitudinal wave, the disturbance in a transverse wave is

Physics
2 answers:
slamgirl [31]3 years ago
4 0

Answer:

The disturbance of molecules are perpendicular to wave motion

Explanation:

Transverse waves: in transverse waves all the medium moles vibrates perpendicular to the wave motion such that the net displacement of all molecules are zero.

While in longitudinal waves all the molecules will oscillate in the direction of wave propagation. All molecules transfer the energy from one point to other point while oscillating parallel to the wave propagation direction.

leva [86]3 years ago
3 0

perpendicular to the wave motion.

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A 65 kilogram astronaut weighs 638 newtons at the surface of earth what is the mass of the astronaut at the surface of the moon,
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The mass of the astronaut is still 65 kilograms. Mass is constant or doesn't change no matter where you are.
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3 years ago
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An injured monkey sits perched on a tree branch 3.0 m above the ground, while a wildlife veterinarian is kneeling down in the bu
Irina18 [472]

here in the given situation if monkey starts free fall at the same instant when veterinarian shoots towards it then we know that vertical component of motion of monkey and the dart will be same as under gravity

so here the dart will always hit the monkey because they both moves under same acceleration

so here for the angle we can use

tan\theta = \frac{H}{L}

now we have

H = 3 m

L = 87.5 m

now we will have

tan\theta = \frac{3}{87.5}

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6 0
3 years ago
HELP!!! 30 POINTS+BRAINLIEST!!!!!QUICK!!
tia_tia [17]

Answer:

A:7.2ms^{-1}

B:14.25ms^{-1}

C:1.45sec

D:10.3m

E:2.9sec

F:20.88m

Explanation:

Let v be the velocity and \alpha be the angle between the velocity and ground.

Question A:

Horizontal component of velocity is given by vcos(\alpha ).

So,horizontal component is 16\times cos(63)=16\times 0.45=7.2ms^{-1}

Question B:

Vertical component of velocity is given by vsin(\alpha ).

So,vertical component is 16\times sin(63)=16\times 0.89=14.25ms^{-1}

Question C:

Time required is given by \frac{\text{vertical component of velocity}}{g}}=\frac{14.25}{9.8}=1.45 seconds

Question D:

Maximum height is given by \frac{\text{vertical component of velocity}^{2}}{2g}}=\frac{203.06}{19.6}=10.3m

Question E:

Time of flight is twice the time required to reach maximum height=2\times 1.45=2.9 seconds.

Question F:

The distance between the player and ball after landing is called range and is given by \text{horizontal component of velocity}\times \text{time of flight}=7.2\times 2.9=20.88m

8 0
3 years ago
a sealed cylinder contains a sample of ideal gas at a pressure of 2.0 atm. The rms speed of the molecules is v0. If the rms spee
fredd [130]

Answer:

P_2 = 1.62 atm

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We know the formula for the rms speed of the ideal gas is  given by

v_{rsm}=\sqrt{\frac{3PV}{m} }

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V= volume of the vessel

m= mass of the gas

Now, From this formula rms speed (v_rms) is directly proportional to square root is pressure.

Then  

\frac{v_{rsm,1}}{v_{rsm,2}} =\sqrt{\frac{P_1}{P_2} }

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putting these values we get

\frac{v0}{0.9v0} =\sqrt{\frac{2}{P_2} }

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8 0
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ikadub [295]

Answer:

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Explanation:

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3 years ago
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