We are given
0.2 M HCHO2 which is formic acid, a weak acid
and
0.15 M NaCHO2 which is a salt which can be formed by reacting HCHO2 and NaOH
The mixture of the two results to a basic buffer solution
To get the pH of a base buffer, we use the formula
pH = 14 - pOH = 14 - (pKa - log [salt]/[base])
We need the pKa of HCO2
From, literature, pKa = 1.77 x 10^-4
Substituting into the equation
pH = 14 - (1.77 x 10^-4 - log 0.15/0.2)
pH = 13.87
So, the pH of the buffer solution is 13.87
A pH of greater than 7 indicates that the solution is basic and a pH close to 14 indicates high alkalinity. This is due to the buffering effect of the salt on the base.
Answer:
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Explanation:
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They're both a part of an atom.
Answer:
they are both equal
Explanation:
if you don't know don't guess troll the teacher you will get it wrong anyway
Answer: 0.450 M H2SO4
Explanation:
To solve this problem, we must remember how to compute molarity. To find the molarity of a solution, we divide the number of moles by the number of liters of solution. Using this formula and substituting the given values, we get:
Molarity = moles solute/liters solution
= 1.35 moles/3.00 L
= 0.450 M H2SO4
Therefore, the correct answer is 0.450 M H2SO4. Note that the answer has 3 significant figures because each of the given values also contains 3 significant figures.
Hope this helps!