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Luden [163]
3 years ago
13

6. Explain why the boiling point of water is a characteristic physical property, but the temperature and volume of a glass of wa

ter are not.
Chemistry
2 answers:
TEA [102]3 years ago
8 0

The physical property is a physical characteristic of a substance at some given conditions

for example

The density of water is 1 g/ mL at STP

The boiling point of water is 373K at 1 atm pressure

so boiling point of water is its physical property. It does not change with amount of the substance. The boiling point of water will remain the same for 1g and 1kg etc

now temperature is an instant measurement, the temperature may vary from sample to sample. Some water sample can be cool or some can be hot. So we cannot define that temperature of all water sample at a given pressure will be the same.

similarly the volume is a not a physical property. It will change from amount to amount.

1g of water sample will have different volume and 100g of water will have different volume while the density of water will remain the same.

NNADVOKAT [17]3 years ago
4 0
A physical property is a property that does not change the original substance, meaning that it does not break any bonds, nor for any new ones. Though, a physical property can be changing the substances state of matter. 

When you are boiling water, you are changing its state to go from a liquid to a gas. The temperature is not a characteristic physical property because it doesn't help us know a lot about that substance, in other words, it isn't significant to the substance. Same goes for volume. 
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Were are electrons located
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Electrons are found in the cloud that's surrounded the nucleus of an atom 
8 0
3 years ago
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What do scientists make to help them make a hypothesis or collect data during an experiment
Veronika [31]
They will most likely make a table, or some sort of graphing chart
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3 years ago
3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution that freezes at −4. 5∘c. what is the molar mass of
enyata [817]

3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution. The molar mass of the solute will be 17.94.

<h3>What is molar mass?</h3>

Molar mass of a substance is its mass in grams in per mole of  a solution.

Freezing point: Freezing point of a substance is a temperature at which a liquid starts to solidify.

Depression in the freezing point can be calculated

[Depression in freezing point of pure solvent—Freezing point of solution] =[(0) - (-4.5)] °C =4.5 °C

molar mass = Number of moles of solute m / Mass of solvent in Kg

3.4g / M x 1/ 0.0783 kg  = 43.42

Substitute AT by 4.5°C , Kr by 1.86 °C/m, and m by 43.42 m in equation (1) as follows:

1.86 x 43.42 / 4.5 = 17.94

Therefore, molar mass of solute to be 17.94.

To learn more about molar mass, refer to the link:

brainly.com/question/22997914

#SPJ4

4 0
2 years ago
Calculate the pH for the following weak acid. A solution of HCOOH has 0.12M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4.
Shtirlitz [24]

Answer:

the pH of HCOOH solution is 2.33

Explanation:

The ionization equation for the given acid is written as:

HCOOH\leftrightarrow H^++HCOO^-

Let's say the initial concentration of the acid is c and the change in concentration x.

Then, equilibrium concentration of acid = (c-x)

and the equilibrium concentration for each of the product would be x

Equilibrium expression for the above equation would be:

\Ka= \frac{[H^+][HCOO^-]}{[HCOOH]}

1.8*10^-^4=\frac{x^2}{c-x}

From given info, equilibrium concentration of the acid is 0.12

So, (c-x) = 0.12

hence,

1.8*10^-^4=\frac{x^2}{0.12}

Let's solve this for x. Multiply both sides by 0.12

2.16*10^-^5=x^2

taking square root to both sides:

x=0.00465

Now, we have got the concentration of [H^+] .

[H^+] = 0.00465 M

We know that, pH=-log[H^+]

pH = -log(0.00465)

pH = 2.33

Hence, the pH of HCOOH solution is 2.33.

7 0
3 years ago
Read 2 more answers
Serial dilution problem: Six test tubes are placed in a rack. To each tube add 4 mL of saline solution. Now to the first tube ad
ArbitrLikvidat [17]

Answer:

The dilution factor of protein in tube # 4 is 125. Molar concentration is 0.0088 M protein

Explanation:

The dilution factor indicates how many times is more concentrated a main solution in relationship with a diluted solution. In this case, the main solution is in tube #1. For calculating the dilution factor and molar concentration in tube #4 we need the main solution concentration which comes from next equation:

Initial volume * initial concentration = final volume * final concentration

0.5 mL * 10M = 5mL * final concentration

1.1 M = final concentration = main solution concentration

Applying the same equation for remain tubes we have 0.22 M for tube #2, 0.044 M for tube # 4 and 0.0088 for tube # 4.

Dilution factor = Main solution concentration/tube 4 concentration

Dilution factor = 1.1/0.0088 = 125

I hope my answer helps you

3 0
3 years ago
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