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Luden [163]
3 years ago
13

6. Explain why the boiling point of water is a characteristic physical property, but the temperature and volume of a glass of wa

ter are not.
Chemistry
2 answers:
TEA [102]3 years ago
8 0

The physical property is a physical characteristic of a substance at some given conditions

for example

The density of water is 1 g/ mL at STP

The boiling point of water is 373K at 1 atm pressure

so boiling point of water is its physical property. It does not change with amount of the substance. The boiling point of water will remain the same for 1g and 1kg etc

now temperature is an instant measurement, the temperature may vary from sample to sample. Some water sample can be cool or some can be hot. So we cannot define that temperature of all water sample at a given pressure will be the same.

similarly the volume is a not a physical property. It will change from amount to amount.

1g of water sample will have different volume and 100g of water will have different volume while the density of water will remain the same.

NNADVOKAT [17]3 years ago
4 0
A physical property is a property that does not change the original substance, meaning that it does not break any bonds, nor for any new ones. Though, a physical property can be changing the substances state of matter. 

When you are boiling water, you are changing its state to go from a liquid to a gas. The temperature is not a characteristic physical property because it doesn't help us know a lot about that substance, in other words, it isn't significant to the substance. Same goes for volume. 
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0.2402 M

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3 years ago
How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?
yawa3891 [41]

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m_{O_2}=120gO_2

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Hello!

In this case, since the decomposition of potassium chlorate is:

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We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2

Best regards!

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