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1 year ago

Someone please explain how this works Which type of reaction occurs in the core of a nuclear reactor in a nuclear power plant?

Chemistry

1 answer:

Paul [167]1 year ago

4 0

An example of a reaction that occurs within the core of a nuclear reactor is the nuclear fission reaction given:

²³⁵₉₂U + ¹₀n ---> ⁹⁰₃₈Sr + ¹⁴³₅₄ + 3 ¹₀n

<h3>What is a nuclear reactor?</h3>

A nuclear reactor is a device which produces electrical energy as a result of the nuclear reactions that take place within it.

In a nuclear reactor, the reaction that takes place within the core is a nuclear fission chain reaction.

In a nuclear fission reaction, the nucleus of larger atoms are split into the nucleus of smaller atoms when fast moving neutrons are used to bombard the nucleus of the large atom. The fission of the nucleus of the large atom results in the formation of atoms of lighter nucleus as well as more protons which then bombard more nucleus of the large atoms resulting in a chain reaction.

The chain reaction occurring within the nuclear reactor core is controlled by the insertion of boron rods which absorbs the excess neutrons produced.

An example of a reaction that occurs within the core of a nuclear reactor is given below:

²³⁵₉₂U + ¹₀n ---> ⁹⁰₃₈Sr + ¹⁴³₅₄ + 3 ¹₀n

Learn more about nuclear fission at: brainly.com/question/913303

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Based on the position of the elements in the periodic table, what is the charge of the ions they are most likely to form?

Rainbow [258]

Explanation:

The charge on an ion denotes the amount of electrons lost or gained or even shared by an atom.

An atom will lose, gain or share an equal amount of electrons that will make it stable and achieve an octet and perfect configuration.

This is often synonymous with the component number of electrons in their outermost shell. The valence shell.

For metals on the periodic table, they are always willing to give up electrons due to their large electropositivity.

Metals will give up the number of electrons in their outermost shell to become stable.

Groups 1 and Group 2 will have charges +1 and +2 on them.

For non-metals , they will gain the exact number of electrons that will make them stable. We must note that half -filled and fully filled orbitals are equally stable.

Elements in groups 6 and 7 are electronegative and will have a charge of -2 and -1 respectively.

For those in groups 3, 4 and 5 they either gain, lose or share commensurate amount of electrons that will make them stable.

Group 8 elements are stable and have no charges.

Generally on the periodic table, metals are to the left and are always positively charged. Non - metals are to the right and are negatively charged.

learn more:

Periodic table brainly.com/question/2690837

#learnwithBrainly

4 0

3 years ago

Given the following: [G3P] = 1.5x10-5M; [BPG] = 3.0x10-3M ; [NAD+] = 1.2x10-5M; [NADH]=1.0x10-4 ; [HPO42-]= 1.2x10-5 M; pH = 7.5

mel-nik [20]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

To calculate the $H^+$ concentration, we use the equation:

$pH=-\log[H^+]$

We are given:

pH of the solution = 7.5

$7.5=-\log [H^+]$

$[H^+]=10^{-7.5)=3.1\times 10^{-8}M$

For the given chemical equation:

$\text{Glyceraldehyde3-phosphate }+NAD^++HPO_4^{2-}\rightarrow \text{1,3-Biphosphoglycerate }+NADH+H^+$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln K_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = 6.3 kJ/mol = 6300 J/mol (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$K_{eq}$ = Ratio of concentration of products and reactants = $\frac{[BPG][NaDH][H^+]}{[G_3P][NAD^+][HPO_4^{2-}]}$

$[BPG]=3.0\times 10^{-3}M$

$[NADH]=1.0\times 10^{-4}M$

$[H^+]=3.1\times 10^{-8}M$

$[G_3P]=1.5\times 10^{-5}M$

$[NAD^+]=1.2\times 10^{-5}M$

$[HPO_4^{2-}]=1.2\times 10^{-5}M$

Putting values in above equation, we get:

$\Delta G=6300J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(3.0\times 10^{-3})\times (1.0\times 10^{-4})\times (3.1\times 10^{-8})}{(1.5\times 10^{-5})\times (1.2\times 10^{-5})\times (1.2\times 10^{-5})}))\\\\\Delta G=9917.02J/mol=9.92kJ/mol$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

As, the Gibbs free energy of the reaction is positive. The reaction is said to be non-spontaneous.

Hence, the given reaction is non-spontaneous in nature.

4 0

3 years ago

Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points

Yanka [14]

Answer:

342.15 g/mol

..........

7 0

2 years ago

Please help I’ll give you the BRAINLIEST!

Simora [160]

Answer:

1. Number of moles in 3.63 * 10²² atoms of K = 0.06 moles

2. Number of moles in 5.96 g of BaCO₃ = 0.03 moles

3. Number of moles of NH₃ = 0.88 moles

4. Volume of CSI = 0.50 liters

Explanation:

1. One mole of K contains 6.02 * 10²³ atoms

Number of moles in 3.63 * 10²² atoms = (3.63 * 10²² atoms/6.02 * 10²³ atoms) * 1 mole

Number of moles in 3.63 * 10²² atoms of K = 0.06 moles

2. Number of moles = mass / molar mass

Molar mass of BaCO₃ = 197.33 g/mol; mass of BaCO = 5.96 g

Number of moles = 5.96 g/ 197.33 g/mol

Number of moles in 5.96 g of BaCO₃ = 0.03 moles

3. Number of moles = mass / molar mass

Molar mass of NH₃ = 17 g/mol; mass of NH₃ = 1.50 g

Number of moles = 1.50 g/ 17 g/mol

Number of moles of NH₃ = 0.88 moles

4. Chlorosulfonyl isocyanate, ClSO2NCO, otherwise known as CSI, is a reagent used in organic synthesis. It has a density of 1.626 g/cm³.

Volume = mass/density

mass = 82.0 g; density of CSI = 1.626 g/cm³

Volume = 82.0 g / 1.626 g/cm³

Volume = 50.43 cm³

Volume = 50.43 cm³/1000 cm³ * 1 liter

Volume of CSI = 0.50 liters

5 0

3 years ago

How to prepare hydrogen gas

Ghella [55]

1. Natural Gas Reforming/Gasification: Synthesis gas, a mixture of hydrogen, carbon monoxide, and a small amount of carbon dioxide, is created by reacting natural gas with high-temperature steam. ...

2. Electrolysis: An electric current splits water into hydrogen and oxygen.

Hope this helps :))

4 0

3 years ago