The answer is it shifts right. This could be explained by Le
Chatelier's principle. It states that that when a system experiences a commotion
(such as absorption, temperature, or heaviness variations), it will answer to reinstate
a new equilibrium state. This just means that if there is an energy added, the
reaction is trying to remove it again by going to the right.
From the statement of Hess' law, the enthalpy of the reaction A---> C is +90 kJ
<h3>What is Hess' law?</h3>
Hess' law of constant heat summation states that for a multistep reaction, the standard enthalpy of reaction is always constant and is independent of the pathway or intermediate routes taken.
From Hess' law, the enthalpy change for the reaction A ----> C is calculated as follows:
A---> C = A ---> B + B ---> C
ΔH of A---> C = 30 kJ + 60 kJ
ΔH = 90 kJ
Therefore, the enthalpy of the reaction A---> C is +90 kJ
The above reaction A---> C can be shown in the enthalpy diagram below:
A -------------------> C (ΔH = +90 kJ)
\ /
\ / (ΔH = +60 kJ)
(ΔH = +30 J) \ /
> B
Learn more about enthalpy and Hess law at: brainly.com/question/9328637
I think Intramolecular forces are being weakened
Answer:
Na the valency electrons is 1
The ion charge is positive 1
K the valency electrons is 1
The ion charge is positive 1
Explanation:
Mg the valency electron is 2 The ion charge is positive 2
Ca the valency electron is 2 The ion charge is positive 2
Al the valency electron is 3 The ion charge is positive 3
O the valency electron is 2 The ion charge
is negative 2
F the valency electron is 1 The ion charge is negative 1
Cl the valency electron is 1 The ion charge
is negative 1
N the valency electron is 3 The ion charge is negative 3
S the valency electron is 2 The ion charge is
negative 2
Answer:
A.
Explanation:
The number of the them will result in A.