Hello!
Recall for resistors in parallel:
We can begin by calculating the total resistance:
Now, we can calculate the current using Ohm's Law:
V = Voltage of battery (V)
i = Current (A)
R = Resistance (Ω)
Plug in the given voltage and the total resistance we solved for.
In the circuit, the total current is 60 A and the voltage is 240 V. If R1
resistance is 20 Ω, then the R2 resistance would be 5 Ω
<h3>What is resistance?</h3>
Resistance is the obstruction of electrons in an electrically conducting material. The SI unit of the resistance is Ohm
The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.
V=IR
where V is the voltage
I is the current
R is the resistance
For the given problem V= 240 V and I = 60 A
R = V/I
R =240/60
R =4 Ω
For calculating equivalent resistance in parallel combination.
1/Re = 1/R1 + 1/R2
1/4 = 1/20 + 1/R2
R2 = 5 Ω
Thus , the R2 resistance would be 5 Ω, therefore the correct answer is option B.
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Oceanic because the theory is that the earth used to only be water
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Below is the solution:
Output work = 108 J.
<span>Input work = 120 J </span>
<span>Efficiency = 108/120 = 9/10 = 90% </span>
<span>(Energy can be converted to heat in friction at the fulcrum, or useless potential energy distorting the crowbar)</span>
Answer:
1.18 mm
Explanation:
The mass of the block is m, so the weight of the block is mg. If the tension in the iron wire is 0.3 mg, then the total tension in the 4 copper wires is 0.7 mg. So the tension in each copper wire is 0.175 mg.
For each wire:
ΔL/L = F / (EA)
where ΔL is the change in length,
L is the initial length,
F is the force,
E is Young's modulus (modulus of elasticity),
and A is the cross sectional area.
The five wires have the same initial length, and stretch by the same amount.
ΔL/L = ΔL/L
F / (EA) = F / (EA)
(0.3 mg) / (2×10¹¹ Pa × π(1.2 mm)²) = (0.175 mg) / (1.2×10¹¹ Pa × πr²)
0.3 / (2 (1.2 mm)²) = 0.175 / (1.2 r²)
0.36 r² = 0.504 mm²
r = 1.18 mm
