Find the work done (in ft-lb) when a constant force F = 18 lb moves a chair from x = 0.6 to x = 1.4 ft.
1 answer:
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Answer:C
Explanation:
Given
weight of object is equal to weight of object
Suppose weight of Planck is W
suppose weight is at distance of x cm from wedge
balancing Torque
i.e. at a distance of 0.25L from the Left end
Answer:
A = 4.49
α = 57.72°
Explanation:
Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.
The angle tangent can be used to determine the angle.
Answer
given,
Electric field,E = 490 N/C
time, t = 54 ns
for electron
Mass of electron me = 9.1 x 10⁻³¹ kg
Charge of electron e = -1.6 x 10⁻¹⁹ C
electrostatic force
F = E q
F = 490 x 1.6 x 10⁻¹⁹
F = 784 x 10⁻¹⁹ N
now, using newton second law
a = 8.62 x 10¹² m/s²
using equation of motion
v = u + a t
v = 0 + 8.62 x 10¹² x 54 x 10⁻⁹
v = 4.65 x 10⁵ m/s
velocity of electron is equal to v = 4.65 x 10⁵ m/s
For Proton
Mass mp = 1.67 x 10⁻²⁷ kg
Charge p = 1.6 x 10⁻¹⁹ C
Electric field E = 490 V/C
from above solution
F = 784 x 10⁻¹⁹ N
now, acceleration
a = 4.69 x 10¹⁰ m/s²
using equation of motion
v = u + a t
v = 0 + 4.69 x 10¹⁰ x 54 x 10⁻⁹
v = 4.65 x 10³ m/s
velocity of electron is equal to v = 4.65 x 10³ m/s