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2 years ago

What will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors?

Physics

1 answer:

dsp732 years ago

8 0

Hello!

Recall for resistors in parallel:
$\frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}$

We can begin by calculating the total resistance:
$\frac{1}{R_t} = \frac{1}{10} + \frac{1}{10} + \frac{1}{10}}\\\\\frac{1}{R_t} = \frac{3}{10}\\\\R_t = \frac{10}{3} = \boxed{3.333 \Omega}$

Now, we can calculate the current using Ohm's Law:
$V = iR\\\\i = \frac{V}{R}$

V = Voltage of battery (V)
i = Current (A)

R = Resistance (Ω)

Plug in the given voltage and the total resistance we solved for.

$i = \frac{15}{3.33} = \boxed{4.5 A}$

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Un ciclista recorre una pista recta de ida y vuelta, en este recorrido:

Elena-2011 [213]

Answer:

a) falso

b) verdadero

c) falso

d) falso

e) verdadero

Explanation:

A) FALSO: la distancia recorrida es independiente del punto de partida y del punto de llegada

B) VERDADERO: para que el ciclista recorra la pista de ida y vuelta es necesario que su velocidad cambie, por lo tanto la aceleración es diferente de cero.

C) FALSO

D) FALSO: en todo momento hay una distancia recorrida en un tiempo en específico, es decir, una rapidez.

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3 years ago

On a cold day you can warm your hands by rubbing them together. (a) Assume that the coefficient of friction between your hands i

melomori [17]

To solve this problem it is necessary to apply the equations related to the Force of Friction and Energy.

By definition the friction force is defined as

$F= \mu * N$

Where,

$\mu =$ Frictional Constant

N = Normal Force -> mg

At the same time we have the definition of the Energy, which can be

E = F*v

Where,

Force

v = Velocity.

Then replacing with our values we have that,

$F = \mu N$

F = 0.5 *34

F = 17

The energy then would be,

E = f v

E = 17 * 0.30 = 5.1 W

Therefore the rate at which heat is generated is 5.1W

6 0

3 years ago

A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a plutonium atom initially at rest. (a) Wh

olga55 [171]

Answer:

Fraction = 59049/60025

Explanation:

Let m be the mass of the neutron and M be the mass of the plutonium nucleus (at rest)

Now, formula for kinetic energy before collision is;

K_i = ½mu²

Formula for kinetic energy after collision is;

K_f = ½mv²

Where;

u is the velocity of the neutron before collision

v is the velocity of the neutron after collision.

From collision principle where momentum before collision equals momentum after collision, we can say that;

(m - M)u = (m + M)v

Thus,

v = [(m - M)u]/(m + M)

Putting [(m - M)u]/(m + M) for v in the final kinetic energy equation gives;

K_f = ½m([(m - M)u]/(m + M))²

K_f = ½mu²((m - M)²/(m + M)²)

To get the fraction of the neutron's kinetic energy is transferred to the plutonium nucleus, it is simply;

K_f/K_i = [½mu²((m - M)²/(m + M)²)]/½mu²

This gives;

K_f/K_i = ((m - M)²/(m + M)²)

But mass of plutonium = 244m

Thus;

K_f/K_i = ((m - 244m)²/(m + 244m)²)

K_f/K_i = 59049m²/60025m²

K_f/K_i = 59049/60025

4 0

3 years ago

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denis23 [38]

Answer:

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8 0

3 years ago

Which one of the following experiments is the justification for the wave theory of light? a. Newton's rings experiment b. Frank-

Lunna [17]

Answer:

Explanation:

double alit experiment is for wave theory for light

4 0

4 years ago

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