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Bond [772]
3 years ago
12

The hypotenuse of a right triangle is 12 centimeters, and the shorter leg is 6 centimeters. Find the length of the other leg.

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0

Answer:

6√3 cm

Step-by-step explanation:

The hypotenuse of a right triangle is 12 centimeters, and the shorter leg is 6 centimeters then the other leg is 6√3

trasher [3.6K]3 years ago
6 0
2nd option.



a^2 + b^2 = c^2

36 + b^2 = 144

b^2 = 108

sqrt(b^2) = sqrt(108)

b = sqrt(108)

b = 6 * sqrt(3)
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Step-by-step explanation:

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3 years ago
HELP What is the area of this figure?
Mademuasel [1]
The correct answer is:  [B]:  "40 yd² " .
_____________________________________________________
First, find the area of the triangle:

The formula of the area of a triangle, "A":

A = (1/2) * b * h ; 

in which:  " A = area (in units 'squared') ;  in our case, " yd² " ; 

                 " b = base length" = 6 yd.  

                 " h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→  A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ; 
                                                                 
                                                                   =  " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:

The formula for the area, "A" of a square:

   A = s² ;

in which:  "A = area (in "units squared") ; in our case, " yd² " ;
                 
                 "s = side length (since a 'square' has all FOUR (4) equal side lengths);

 A = s²  = (4 yd)² = 4² * yd² =  "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
        →  " 24 yd²  +  16 yd² " ; 

to get:  " 40 yd² " ;  which is:  Answer choice:  [B]:  " 40 yd² " .
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