Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Y=2 yes (the slope is 0 and the y intercept is 2)
Answer:
440
Step-by-step explanation:
1.5 hours he 90 minutes
660/ 90=7.333
7.333*60 (which is how many minutes in an hour = 440 miles
38% of 21,515,714 is 8175971.32 which can be rounded to 8,175,971.
Hope this helps :)<span>
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