(0.5)×(0squared)×(3)=(1.5j)
Answer:
v = -5 m/s
Explanation:
It is given that,
The initial velocity of the ball, u = 25 m/s
We need to find its velocity after 2 seconds in the air.
Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.
v = u + at
Here, a = -g
v = u -gt
Putting all the values,
v = 25 - (10)(3)
= 25-30
= -5 m/s
So, the velocity of the ball after 3 seconds is 5 m/s and it is in downward direction.
Left. Use right hand rule. Have hand wide open. Thumb points in direction of current.(which makes right angle with your index finger) Four fingers in direction of magnetic field and your palm should point in the direction of the force
Answer:
Explanation:
The formula S=(at^2)/2 will be used during the entire explanation.
1. 4 = (2t^2)/2
t = 2 s.
V = at = 2 * 2 = 4 m/s
2. 8 = (2t^2)/2
t = 2.8 s
iii. 2s
iv. 2.8 - 2 = 0.8s
Hope you understand)
Answer:
I know one answer is an observer on earth sees a lunar eclipse
