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chubhunter [2.5K]
3 years ago
10

What are two things that determine our traits? If someone could answer asap, that would be awesome!

Physics
2 answers:
Pavlova-9 [17]3 years ago
7 0
Genes and the environment
zepelin [54]3 years ago
5 0
In thinking about inherited traits, geneticists use two important words: genotype and phenotype. Genotype refers to the genes an organism inherits from its parents and phenotype refers to the observable characteristics of an organism: how it develops, looks, reacts and behaves. An inherited trait refers to a phenotypic characteristic, for example flower color, length of gestation or ability to metabolize cellulose. All traits have a genetic basis.
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23.5 DEGREES is the answer. 
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Which type of physical activity is being performed in the picture?
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B strength training I think that’s the answer
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For a 50 kV anode voltage, what is the maximum photon energy of the x-ray radiation?
V125BC [204]

Answer:

The energy of photon, E=8\times 10^{-15}\ J

Explanation:

It is given that,

Voltage of anode, V=50\ kV=50\times 10^3\ V=5\times 10^4\ V

We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.

E=eV

e is charge of electron

E=1.6\times 10^{-19}\times 5\times 10^4

E=8\times 10^{-15}\ J

So, the maximum energy of the x- ray radiation is 8\times 10^{-15}\ J. Hence, this is the required solution.

6 0
3 years ago
If K= -3 and n= 9 what is -5+-3-9​
kherson [118]

Answer:

-17

Explanation:

8 0
3 years ago
Four point masses of 3.0 kg each are arranged in a square on masslessrods. The length of a side of the square is 0.50m. What is
Zigmanuir [339]

Answer:

Part a)

I = 1.5 kg m^2

Part b)

I = 0.75 kg m^2

Part c)

I = 1.5 kg m^2

Explanation:

Part a)

Moment of inertia of the system about an axis passing through B and C is given as

I = mL^2 + mL^2 + m(0) + m(0)

I = 2mL^2

I = 2(3 kg)(0.50^2)

I = 1.5 kg m^2

Part b)

Moment of inertia of the system about an axis passing through A and C is given as

I = m(0^2) + m(\frac{L}{\sqrt2})^2 + m(0) + m(\frac{L}{\sqrt2})^2

I = 2m\frac{L^2}{2}

I = (3 kg)(0.50^2)

I = 0.75 kg m^2

Part c)

Moment of inertia of the system about an axis passing through the center of the square and perpendicular to the plane of the square

I = m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2

I = 4m\frac{L^2}{2}

I = 2(3 kg)(0.50^2)

I = 1.5 kg m^2

8 0
3 years ago
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