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3 years ago

What concentration of so32– is in equilibrium with ag2so3(s) and 9.50 × 10-3 m ag ? the ksp of ag2so3 can be found here?

1 answer:

8 0

Answer is: concentration of SO₃² is 1.66·10⁻¹⁰ M.
Reaction of dissociation: Ag₂SO₃(s) → 2Ag⁺(aq) + SO₃²⁻(aq).
Ksp for silver sulfite is 1.5·10⁻¹⁴.
c(Ag⁺) = 9.50·10⁻³ M; equilibrium concentration of silver cations.
Ksp = c(Ag⁺)² · c(SO₃²⁻).
c(SO₃²⁻) = Ksp ÷ c(Ag⁺)².
c(SO₃²⁻) = 1.5·10⁻¹⁴ M³ ÷ (9.50·10⁻³ M)².
c(SO₃²⁻) = 1.5·10⁻¹⁴ M³ ÷ 9.025·10⁻⁵ M².
c(SO₃²⁻) = 1.66·10⁻¹⁰ M; equilibrium concentration of sulfite anions.

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1 year ago

Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

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Answer : The volume of $CO_2$ will be, 514.11 ml

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$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

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Now we have to calculate the moles of $HCO_3^-$ .

Molar mass of $HCO_3^-$ = 1 + 12 + 3(16) = 61 g/mole

$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

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3 years ago

Calculate the Standard Enthalpy of the reaction below:

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3 years ago

Calculate the percent errorin a length measurementof 4.45cm if the correct value is 4.06

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Answer:

9.6 %

Explanation:

Step 1: How to define percent error ?

⇒ % error is the difference between a measured value and the known or accepted value

⇒Percent error is calculated using the following formula:

⇒%error = | Experimental value-theoretical value/theoretical value | x100%

⇔ this can be written as well as : error = (| Experimental value/ theoretical value | - | Theoretical value / Theoretical value | ) x100%

Step 2: Calculate % error

In this case, this means :

%error = ( |(4.45 cm - 4.06cm ) / 4.06cm | ) x100%

%error = 0.096 x100%

%error =9.6 %

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