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Vera_Pavlovna [14]
3 years ago
13

What concentration of so32– is in equilibrium with ag2so3(s) and 9.50 × 10-3 m ag ? the ksp of ag2so3 can be found here?

Chemistry
1 answer:
satela [25.4K]3 years ago
8 0
Answer is: concentration of SO₃² is 1.66·10⁻¹⁰ M.
Reaction of dissociation: Ag₂SO₃(s) → 2Ag⁺(aq) + SO₃²⁻(aq)<span>.
Ksp for silver sulfite is 1.5</span>·10⁻¹⁴.
c(Ag⁺) = 9.50·10⁻³ M; equilibrium concentration of silver cations.
Ksp = c(Ag⁺)² · c(SO₃²⁻).
c(SO₃²⁻) = Ksp ÷ c(Ag⁺)².
c(SO₃²⁻) = 1.5·10⁻¹⁴ M³ ÷ (9.50·10⁻³ M)².
c(SO₃²⁻) = 1.5·10⁻¹⁴ M³ ÷ 9.025·10⁻⁵ M².
c(SO₃²⁻) = 1.66·10⁻¹⁰ M; equilibrium concentration of sulfite anions.
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Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
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Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

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HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

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\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

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P = pressure of gas = 1.00 atm

V = volume of gas = ?

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R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

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