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Vera_Pavlovna [14]
3 years ago
13

What concentration of so32– is in equilibrium with ag2so3(s) and 9.50 × 10-3 m ag ? the ksp of ag2so3 can be found here?

Chemistry
1 answer:
satela [25.4K]3 years ago
8 0
Answer is: concentration of SO₃² is 1.66·10⁻¹⁰ M.
Reaction of dissociation: Ag₂SO₃(s) → 2Ag⁺(aq) + SO₃²⁻(aq)<span>.
Ksp for silver sulfite is 1.5</span>·10⁻¹⁴.
c(Ag⁺) = 9.50·10⁻³ M; equilibrium concentration of silver cations.
Ksp = c(Ag⁺)² · c(SO₃²⁻).
c(SO₃²⁻) = Ksp ÷ c(Ag⁺)².
c(SO₃²⁻) = 1.5·10⁻¹⁴ M³ ÷ (9.50·10⁻³ M)².
c(SO₃²⁻) = 1.5·10⁻¹⁴ M³ ÷ 9.025·10⁻⁵ M².
c(SO₃²⁻) = 1.66·10⁻¹⁰ M; equilibrium concentration of sulfite anions.
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<em />

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Protons have relative positive charge equal to +1 and electrons have relative negative charge -1: same magnitude opposite sign.

Thus, the neutral oxygen, O, has also 8 electrons and 8 protons.

As per the number neutrons it depends on the specific isotope.

The isotopes are identified by the mass number, which is the number of protons plus neutrons. For instance, oxygen-16 isotope has mass number 16, 8 protons and 8 neutrons, while oxygen-15 isotope has mass number 15, 8 protons and 7 neutrons.

Oxide ion O²⁻ is the oxygen ion with -2 charge, meaning that it has 2 more electrons than protons. Then, it has 8 protons and 10 electrons, again the number of neutrons depend of the specific isotope.

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