Molecular mass of Mg(OH)2
= Atomic mass of Mg + 2(Atomic mass of O) + 2(Atomic mass of H)
= 24 g/mol + 2(16 g/mol) + 2(1 g/mol )
= 58 g/mol
Molecular mass of Fe2O3
= 2(Atomic mass of Fe) + 3(Atomic mass of O)
= 2(56 g/mol) + 3(16 g/mol)
= 160 g/mol
Answer:
The balanced equation is 2K(s) + Cl2(g)→2KCl(s)
In order to solve the total pressure that is exerted by the gases, we need to use the Dalton's Law of Partial pressures. These are the calculations that you need to find out the total amount of pressure exerted to the gases:
3.00atm (N2) + 1.80atm (O2) + 0.29atm (Ar) + 0.18atm (He) + 0.10atm (H),
add up all of that, and the answer would turn out to be: 5.37atm.
D) 710 g
Step by Step:
Multiply 2.5 L by 2.0 M to solve for moles
2 mol/L • 2.5 L= 5 mol
Find formula weight of sodium sulfate
Na2SO4-142.04 g/mol
Na- 2(22.99)=45.98
S-32.06
O-4(16)=64
Multiply miles by formula weight
5 mole • 142.04 g/mol=710.2 g
6.2 grams of CO2 = 1.408786739226764 moles
