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const2013 [10]
3 years ago
9

How does volvox differ from other protists

Chemistry
1 answer:
Dovator [93]3 years ago
7 0
It differs because it is a unicellular plant. Many scientists claim that Volvoxes are protists while many claim that they are plants, and protists are not plants.
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Assuming you have 6.24 x 1014 electrons and the surface area of the pail is 0.2 m2, what is the charge density (C/m2)?
pentagon [3]

Answer:

σ = 4.998 E-4 C/m²

Explanation:

  • 1 Coulomb (C) ≡ 6.241509 E18 electrons (e)

∴ # elect = 6.24 E14 elect

charge (Q):

⇒ Q = (6.24 E14 elect)/( 1 C /6.241509 E18 elect) = 9.998 E-5 C

charge density (σ):

  • σ = Q/S

∴ surface area (S) = 0.2 m²

⇒ σ = ( 9.998 E-5 C ) / ( 0.2 m²)

⇒ σ = 4.998 E-4 C/m²

4 0
3 years ago
luminum and oxygen react according to the following equation: 4Al(s) +3O2(g) --> 2Al2O3(s) What mass of Al2O3, in grams, can
Slav-nsk [51]

Answer: 8.7 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{4.6g}{27g/mol}=0.17moles

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

As oxygen is in excess, Aluminium is the limiting reagent and limits the formation of products.

According to stoichiometry:

4 moles of aluminium give = 2 moles of Al_2O_3(s)

Thus 0.17 moles of aluminium give=\frac{2}{4}\times 0.17=0.085mol

Mass of Al_2O_3=moles\times {\text {molar mass}}=0.085\times 102g/mol=8.7g

Thus the mass of Al_2O_3(s)  is 8.7 grams

8 0
3 years ago
How are these 3 types of rocks related/ similar?
Anastasy [175]

Answer:

The rock cycle

Explanation:

The three types of rocks are related and connected through the rock cycle. Rocks are not formed independently of one another, the process of their formation are interconnected.

 Igneous rocks are made from cooling and solidification of magma. These magma are derived from the melting of rocks that have been subjected to high temperature and pressure.

 When igneous rocks are formed, they can follow two path ways. They either get transformed to sedimentary rocks or metamorphic rocks.

When igneous rocks are subjected to metamorphic conditions, their mineralogy is altered to form metamorphic rocks.

If igneous rocks gets weathered and broken down by agents of denudation, they end up getting transformed into sedimentary rocks.

5 0
3 years ago
A 13-gram rubber stopper is attached to a 0.93-meter
makkiz [27]
<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

  • Mass of rubber stopper = 13 g
  • Length of the string(radius) = 0.93 m
  • Time for one revolution = 1.18 seconds

We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

             = 4.953 m/s

Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

                                        = 26.38 m/s²

Hence, the centripetal acceleration is 26.38 m/s²

6 0
3 years ago
For the galvanic (voltaic) cell Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s) (E°= 0.77 V at 25°C), what is [Fe2+] if [Mn2+] = 0.040 M and
avanturin [10]

Answer:

0.01836 M

Explanation:

Again the reaction equation is;

Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s)

E°cell= 0.77 V

Ecell= 0.78 V

[Mn2+] = 0.040 M

[Fe2+] = the unknown

n=2

From Nernst's equation;

Ecell= E°cell- 0.0592/n log Q

0.78= 0.77 - 0.0592/2 log [Fe2+] /[0.040]

0.78-0.77= - 0.0592/2 log [Fe2+] /[0.040]

0.01/ -0.0296= log [Fe2+] /[0.040]

-0.3378= log [Fe2+] /[0.040]

Antilog(-0.3378) = [Fe2+] /[0.040]

0.459= [Fe2+] /[0.040]

[Fe2+] = 0.459 × 0.040

[Fe2+] = 0.01836 M

7 0
3 years ago
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