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Novosadov [1.4K]
3 years ago
9

What is the area of shore between high and low tides called

Physics
1 answer:
Triss [41]3 years ago
8 0

Its is called intertidal zone

Explanation:

The earth rotation and the moon's pull of gravity causes the tides to rise and fall.High tides occur when the water advances to the furthers point of a shoreline where as low tides happen when the water recedes to the lowest point of the shoreline.Some kinds of animal and plants survive in the ecosystem present between the area of high tides and low tides refered to as the intertidal zone.This area is sometimes covered or uncovered by ocean waters.

Learn More

Intertidal zone:brainly.com/question/1346004

Keywords: area, shoreline, high tides, low tides.

#LearnwithBrainly

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26. A 40 kg boy jumps from a height of 4m onto a plate-form mounted on springs. As the
denpristay [2]

Answer:

c. 1600J

Explanation:

The loss in potential energy of the boy is given by:

U=mg \Delta h

where

m = 40 kg is the mass of the boy

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h = 4 m + 0.02 m = 4.02 m is the total change in the height of the boy (4 metres + 2 cm due to the compression of the spring)

Substituting, we find

\Delta U = (40 kg)(9.8 m/s^2)(4.02 m) = 1577 J \sim 1600 J

4 0
3 years ago
What is the force required to stop a 20 kg man traveling at 12.3 m/s East in 0.9 s? *Round to TWO decimal points and include you
abruzzese [7]

F = ma

We have mass = 20kg

And we need to solve for acceleration

So acceleration is change in velocity over time, in this case we have one velocity and we can assume the man started from rest so

12.3 / 0.9 = a

a = 13.6667

Now we can plug that into F = ma

F = (20)(13.6667)

F = 273.334

Rounding

F = 273.33

Now he is traveling east so we need a force towards the rest, or in the opposite direction to stop his motion.

If we assume east is the positive direction then we need a force of

-273.33 N to stop the man or 273.33 towards the west.

4 0
4 years ago
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
aliina [53]

Answer:

v_f = 10.38 m / s

Explanation:

For this exercise we can use the relationship between work and kinetic energy

          W = ΔK

note that the two quantities are scalars

Work is defined by the relation

          W = F. Δx

the bold are vectors.  The displacement is

          Δx = r_f -r₀

          Δx = (11.6 i - 2j) - (4.4 i + 5j)

          Δx = (7.2 i - 7 j) m

 

          W = (4 i - 9j). (7.2 i - 7 j)

remember that the dot product

           i.i = j.j = 1

           i.j = 0

           

           W = 4  7.2 + 9  7

           W = 91.8 J

the initial kinetic energy is

           Ko = ½ m vo²

           Ko = ½ 2.0 4.0²

           Ko = 16 J

we substitute in the initial equation

          W = K_f - K₀

          K_f = W + K₀

          ½ m v_f² = W + K₀

          v_f² = 2 / m (W + K₀)

          v_f² = 2/2 (91.8 + 16)

           v_f = √107.8

          v_f = 10.38 m / s

3 0
3 years ago
aving established that a sound wave corresponds to pressure fluctuations in the medium, what can you conclude about the directio
vovangra [49]

Answer: Pressure fluctuations travel along the direction of propagation of the sound wave.

Explanation:

Sound wave is a type of longitudinal wave. It is defined as a wave which consist of vibrations of particles traveling through a medium( such as air, or water).

Sound wave is propagated by the alternating adiabatic compression and expansion of the medium. The COMPRESSIONS are regions of high air pressure while the RAREFACTIONS are regions of low air pressure. Therefore, Since a sound wave consists of a repeating pattern of high-pressure and low-pressure regions moving through a medium, it is sometimes referred to as a PRESSURE WAVE.

The direction of the vibrating particles is parallel to the direction of propagation and that's why it's a type of LONGITUDINAL WAVE. Therefore, the correct option that

concludes about the direction in which such pressure fluctuations travel is

(Pressure fluctuations travel along the direction of propagation of the sound wave.)

8 0
3 years ago
HURRY!!!!!!!!!!!
iren2701 [21]

The density of a substance is the ratio of its mass to its volume. So whatever volume you have (call it V), the density \rho is computed by

\rho=\dfrac{200\,\mathrm g}V

6 0
3 years ago
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