The square plates of a 3000-pF parallel-plate capacitor measure 40 mm by 40 mm and are separated by a dielectric that is 0.29 mm
1 answer:
You might be interested in
Answer:
a) 37171
b) sec
Explanation:
m = mass of the weight being lifted = 60.0 kg
d = distance by which the weight is lifted = 0.670 m
E = Energy available to burn = 1 lb = 3500 kcal = 3500 x 4184 J
g = acceleration due to gravity = 9.8 m/s²
n = number of times the weight is lifted
Energy available to burn is given as
E = n m g d
3500 x 4184 = n (60) (9.8) (0.670)
n = 37171
b)
T = time period for each lift up = 1.80 s
t = total time taken
Total time taken is given as
sec
Answer:
The pressure is constant, and it is P = 150kpa.
the specific volumes are:
initial = 0.062 m^3/kg
final = 0.027 m^3/kg.
Then, the specific work can be written as:
The fact that the work is negative, means that we need to apply work to the air in order to compress it.
Now, to write it in more common units we have that:
1 kPa*m^3 = 1000J.
-5.25 kPa*m^3/kg = -5250 J/kg.