Your friend states in a report that the average time required to circle a 1.5-mi track was 65.414 s. This was measured by timing
1 answer:
The time per lap was calculated by measuring the time for seven laps and dividing the total time by seven.
total time
It is given that the precision is of 0.1 s. it means it is correct upto 1 place beyond decimal.
So, the actual value could vary from 457.800 s to 457.899 s i.e. the time per lap could be 65.400 s to 65.414 s
It means measured time 65.414 s has maximum error of 0.021%. Hence, the measured value is quite precise.
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Answer:
Explanation:
When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:
where
q is the charge
v is its velocity
B is the strength of the magnetic field
Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:
where
m is the mass of the particle
r is the radius of the orbit of the particle
The equation can be re-arranges as
where in this problem we have:
is the magnitude of the charge of the electron
is the strength of the magnetic field
The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,
is the mass of the electron
So, the electron's speed is
It is given that the length of blade of the turbine is 58 m.
During the motion, the turbine will undergo rotational motion. Hence the radius of the circle traced by the turbine is equal to the length of the blade.
Hence radius r = 58 m.
The frequency of the turbine [f] =14 rpm.
Here rpm stands for rotation per minute.
Hence the frequency of the turbine in one second-
Here Hz[ hertz] is the unit of frequency.
The angular velocity of the turbine
radian/second
Now we have to calculate the centripetal acceleration of the blade.
Let the linear velocity of the blade is v.
we know that linear velocity v=ωr
The centripetal acceleration is calculated as-
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