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RoseWind [281]
3 years ago
13

Represent 0.00563 mg as a number between 0.1 and 1000 using an appropriate prefix Express your answer to three significant figur

es and include the appropriate units. 2 ? "! HAR 0.00563 mg = 5.63 . 10-3 O mg
Physics
1 answer:
Tems11 [23]3 years ago
7 0

Answer:

5.63 microgram (μg)

Explanation:

Here mass is given in miligram

Some of the prefixes of the SI units are

1 gram = 10⁻³ kilogram

1 milligram = 10⁻⁶ kilogram

1 microgram = 10⁻⁹ kilogram

1 nanogram = 10⁻¹² kilogram

1 microgram = 10⁻³ miligram

The number is 0.783

Here, the only solution where the number of significant figures is three is microgram. If any other prefix is chosen then the significant figures will increase.

1\ miligram = 1000\ microgram

\\\Rightarrow 0.00563\ miligram=0.00563\times 1000\ microgram\\ =5.63\ microgram

So, 0.00563 miligram = 5.63 microgram

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If two variables have a non-related relationship and one of the variables is changed, how will the other variable change?
PolarNik [594]

If one of the variables is changed, that tells nothing about what happens to the other one, or IF anything happens, or when, or how long it lasts. Because they are UN-RELATED. You just said so yourself.

None of the choices says this.

6 0
3 years ago
A man stands at the edge of a cliff and throws a rock downward with A speed of 12.0 m s . Sometimes later it strikes the ground
kvasek [131]

B) 48.0 m/s

We can actually start to solve the problem from B for simplicity.

The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

v^2 -u^2 = 2as

where

v is the final velocity

u = 12.0 is the initial velocity (positive since we take downward as positive direction)

a=g=9.8 m/s^2 is the acceleration of gravity

s = 110 m is the vertical displacement

Solving for v, we find the final velocity (and so, the speed of the rock at impact):

v = \sqrt{u^2+2as}=\sqrt{12^2+2(9.8)(110)}=48.0 m/s

A) 3.67 s

Now we can find the time of flight of the rock by using the following suvat equation

v=u+at

where

v = 48.0 is the final velocity at the moment of impact

u = 12.0 is the initial velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time it takes for the rock to reach the ground

And solving for t, we find

t=\frac{v-u}{a}=\frac{48.0-12.0}{9.8}=3.67 s

6 0
3 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me
lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh

We also know that

V=\pi r^2h

dV= 2\pi h dr + \pi r^2 dh

Given that

h= 10 cm

d=10 cm ,  r= 5 cm

Thickness = 0.05 cm so  dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick  so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

dV= 2\pi h dr + \pi r^2 dh

dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3

dV = 32.98 cm³

8 0
3 years ago
A ball is thrown horizontally at 25.8m/s from 54 meter high cliff. How far from the base of the cliff does the ball land?
mario62 [17]

Answer:

85.66m

Explanation:

Given the following data;

Horizontal velocity = 25.8m/s

Height = 54m

Initial velocity = 0

We would first of all, solve for the time taken using the formula for maximum height of a projectile.

H = ½gt²

Where;

  • H is the maximum height measured in meters.
  • g represents the acceleration due to gravity measured in meters per seconds square.
  • t represents the time taken measured in seconds.

We know that acceleration due to gravity is 9.8m/s²

Substituting into the equation

54 = ½*9.8t²

54 = 4.9t²

t² = 54/4.9

t² = 11.02

t = 3.32 secs

To find the distance;

Distance, x = velocity * time

x = vt

Substituting into the equation, we have;

x = 25.8*3.32

x = 85.66m

3 0
3 years ago
A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
Vaselesa [24]

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

5 0
4 years ago
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