If one of the variables is changed, that tells nothing about what happens to the other one, or IF anything happens, or when, or how long it lasts. Because they are UN-RELATED. You just said so yourself.
None of the choices says this.
B) 48.0 m/s
We can actually start to solve the problem from B for simplicity.
The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

where
is the final velocity
is the initial velocity (positive since we take downward as positive direction)
is the acceleration of gravity
s = 110 m is the vertical displacement
Solving for v, we find the final velocity (and so, the speed of the rock at impact):

A) 3.67 s
Now we can find the time of flight of the rock by using the following suvat equation

where
is the final velocity at the moment of impact
is the initial velocity
is the acceleration of gravity
t is the time it takes for the rock to reach the ground
And solving for t, we find

Answer:
dV = 32.98 cm³
Explanation:
We know that
V = f ( h,r)

We also know that


Given that
h= 10 cm
d=10 cm , r= 5 cm
Thickness = 0.05 cm so dr = 0.05 cm
The metal in the top and the bottom is 0.2 cm thick so dh = 0.2 + 0.2 cm
dh = 0.4 cm
Now by putting the values


dV = 32.98 cm³
Answer:
85.66m
Explanation:
Given the following data;
Horizontal velocity = 25.8m/s
Height = 54m
Initial velocity = 0
We would first of all, solve for the time taken using the formula for maximum height of a projectile.
H = ½gt²
Where;
- H is the maximum height measured in meters.
- g represents the acceleration due to gravity measured in meters per seconds square.
- t represents the time taken measured in seconds.
We know that acceleration due to gravity is 9.8m/s²
Substituting into the equation
54 = ½*9.8t²
54 = 4.9t²
t² = 54/4.9
t² = 11.02
t = 3.32 secs
To find the distance;
Distance, x = velocity * time
x = vt
Substituting into the equation, we have;
x = 25.8*3.32
x = 85.66m
Answer:
The greatest speed of the car is 19.36m/s
Explanation:
The maximum speed the car will attain without skidding is given by:
F= uN = umg ...eq1
But F = mv^2/r
mv^2/r = umg
Dividing both sides by m, leaves you with:
V= Sqrt(ugr)
Where u = coefficient of static friction
g = acceleration due to gravity
r = raduis
Given:
U = 0.82
r=0.82
g= 9.8m/s
V = Sqrt(0.82 × 9.8 × 45)
V = Sqrt(374.85)
V = 19.36m/s