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melisa1 [442]
3 years ago
5

A heater coil connected to 240-Vrms ac line has a resistance of 31 Ω . Part APart complete What is the average power used? Expre

ss your answer to two significant figures and include the appropriate units. P¯¯¯¯ = 1900 W Previous Answers Correct Part B What is the maximum value of the instantaneous power?
Physics
1 answer:
Mariulka [41]3 years ago
4 0

Answer:

a) 1857.6 W

b) 3713.036 W          

Explanation:

Given:

V_{rms}=240V\\R=31\Omega

Average current, I=\frac{240V}{31\Omega}=7.74 A

Average power, P=VI=240\times 7.74=1857.6W

Peak current:

I_p=\sqrt2 I\\I_p=\sqrt 2 \times 7.74=10.94A\\

Peak Voltage:

V_p=\sqrt2 V\\V_p=\sqrt2 \times 240 =339.4 V

Maximum value of instantaneous Power is

P_{max}=I_p\times V_p\\P_{max}=10.94\times 339.4 = 3713.036 W

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Wow! That's fast!

<u>We now have our answers for a and b:</u>

a. 49 (m/s)

b. 9.2 * 10^{3} (m/s^{2})

If you have any questions on how I got to these answers, just ask!

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The formula is Work = torque * angle.

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The resultant force on the positive charge  is mathematically given as

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<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>

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Three-point charges, two positive and one negative, each having a magnitude of 20

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