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matrenka [14]
3 years ago
14

What stores energy for a quick release in a cell?

Physics
1 answer:
luda_lava [24]3 years ago
5 0
It is the mitochondria of a cell that stores energy for a quick release. <span>Mitochondria break down glucose to release the energy for cells to use. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
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Now it's your turn
eduard

Answer:

The average force the golf club exerts on the ball is 600 N

Explanation:

Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced

F = m× (v₂ - v₁)/(Δt)

The given parameters of the motion of the ball are;

The mass of the ball, m = 45 g = 0.045 kg

The initial velocity of the ball, v₁ = 0 m/s

The speed with which the ball was hit by the golfer, v₂ = 40 m/s

The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)

By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;

F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N

The average force the golf club exerts on the ball = F = 600 N.

5 0
3 years ago
What is it called when a skydiver is no longer accelerating downward?
raketka [301]

Explanation:

Once the force of air resistance is as large as the force of gravity, a balance of forces is attained and the skydiver no longer accelerates. The skydiver is said to have reached a terminal velocity.

4 0
3 years ago
A woman lifts her 150 N child up one meter and carries her for a distance of 50 meters to the
Cloud [144]

7500J

Explanation:

Given parameters:

Weight of child = 150N

Height of lifting = 50m

Distance = 50m

Unknown:

Work done by the woman = ?

Solution:

Work done by a body is the force applied to move a body through a given distance.

  Work done = Force x distance

Weight is a force impacted by the mass of a body and the gravity on it.

 input the parameters:

   Work done = 150 x 50 = 7500J

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

3 0
3 years ago
A particle is projected with velocity v0 directly up a slope which makes an angle α with the horizontal. Assume frictionless mot
Nikolay [14]

Answer:

a)T total = 2*Voy/(g*sin( α ))

b)α = 0º ,  T total≅∞ (the particle, goes away horizontally indefinitely)

α = 90º,  T total=2*Voy/g

Explanation:

  • Velocity in the Y axis:

Voy=Vo*sinα

  • Time to reach the maximal height :

Kinematics equation: Vfy=Voy-at

a=g*sinα ;  g is gravity

if Vfy=0 ⇒ t=T ; time to reach the maximal height

so:

0=Voy-g*sin( α )*T

T=Voy/(g*sin( α ))

  • Time required to return to the starting point:

After the object reaches its maximum height, the object descends to the starting point, the time it descends is the same as the time it rises.

So T total= 2T = 2*Voy/(g*sin( α ))

  • α = 0º , sinα=0

The particle goes totally horizontal, goes away indefinitely

T total= 2*Voy/(g*sin( α )) ≅∞

  • α = 90º, sinα=1

T total=2*Voy/g

6 0
3 years ago
Scientific investigations
snow_tiger [21]
I don’t know what you are trying to ask complete my but here are the steps to a scientific investigation i hope this helps you

6 0
3 years ago
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