1.806x10^24
Written equation form(always start the equation off with what you know based off of the question!):
3mol(CCl4)•6.022x10^23/1mol = 1.806x10^24
Good luck!
Answer:
P₂ = 3.19 atm
Explanation:
Given data:
Initial volume = 700 mL
Initial pressure = 1 atm
Initial temperature = 273K
Final temperature =100°C (100+273= 373 K)
Final volume = 300 mL
Final pressure = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₂ = P₁V₁ T₂/ T₁ V₂
P₂ = 1 atm × 700 mL × 373K / 273 K ×300 mL
P₂ = 261100 atm .mL. K /81900 K .mL
P₂ = 3.19 atm
They all have their different measurements like the volume of a liquid can be measured in a lab with a beaker.