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Drupady [299]
3 years ago
15

When the equation is correctly balanced, the coefficient of aluminum chloride will be ___.

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
7 0

The answer for the following question is answered below.

<em>Therefore when the equation is balanced the co-efficient of aluminium chloride will be 2.</em>

Explanation:

The balanced equation for the following equation is:

AlCl_{3} + Ba(OH)_{2}  → Al(OH)_{3} + BaCl_{2}

To balance an equation:

  • Firstly we have to see whether the elements on the reactants and products side are same or not.
  • Then balance each element and see whether the equation  is balanced or not

<em>When 2 moles of aluminium chloride react with 3 moles of barium hydroxide on the reactants side then on the products side it yields 2 moles of aluminium hydroxide and 3 moles of barium chloride </em>

(i.e.)

2AlCl_{3} + 3Ba(OH)_{2}  → 2Al(OH)_{3} + 3BaCl_{2}

<em><u>Therefore when the equation is balanced the co-efficient of aluminium chloride will be 2.</u></em>

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How to find the final product of Fe (II) + CI ?
pickupchik [31]

The valency of iron (Fe) in this equation is 2

While, the valency of chlorine is 1

Therefore, we know that iron wants to give away 2 electrons to attain octet configuration, and chlorine wants to get an electron to attain octet configuration.

Also while find the products the number of atoms is similar to the oppostie valency

Fe = 1 atom , Cl = 2 atoms

Which will form FeCl₂

Happy to help :)

If you need any help pls ask

5 0
2 years ago
A 10.0 mL sample of household ammonia solution required38.50 mL of 0.311 M HCl to achieve neutralization. Calculate (a).the mola
DaniilM [7]

Answer:

a) 1.1974 M

b) 2.07%

Explanation:

In this case, we have a neutralization reaction between the HCl and ammonia, the acid base reaction is as follow:

HCl + NH₃ --------> NH₄⁺ + Cl⁻

a) As we can see, we have a 1:1 mole ration between the acid and the base, therefore we can use the following expression to calculate concentration of the ammonia:

M₁V₁ = M₂V₂

Replacing the data in here, we can solve for the concentration of ammonia:

M₂ = M₁V₁ / V₂

M₂ = 0.311 * 38.50 / 10

M₂ = 1.1974 M

This is the concentration of the ammonia solution.

b) Now we want to know the mass percent, in this case, we need to calculate the moles of ammonia first, and then, turn it into mass using the molar mass given (17 g/mol):

n = 1.1974 * 0.010 = 0.011974 moles

m = 0.011974 * 17 = 0.2036 g

The solution has a density of 0.983 g/mL and we have 10 mL therefore, we should have of mass:

d = m/V

m = d * V

m = 0.983 * 10 = 9.83 g

Finally the mass percent will be:

% = 0.2036 / 9.83 * 100

% = 2.07%

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3 years ago
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Answer: A helium atom is an atom of the chemical element helium. Helium is composed of two electrons bound by the electromagnetic force to a nucleus containing two protons along with either one or two neutrons

hope its help

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