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Semenov [28]
2 years ago
6

Class 11th physics the charge of positive 7 microcoulomb is placed at the centre of two concentric sphere with radius 2cm and 4c

m respectively what will be the ratio of flux through them
Physics
1 answer:
Talja [164]2 years ago
7 0

<em><u>Given</u></em>:

  • If the charge of +7 mC is placed at the centre of two concentric spheres with the radius 2.0cm and 4.0cm respectively

<em><u>Need to find</u></em> :

  • Ratio of the flux through them will be ?

<em><u>Calculation</u></em>:

<em><u>Gauss law</u></em> :- ø = q/Eₒ

1. For small sphere:- ø1 = q/Eₒ

2. For large sphere :- ø2 = q/Eₒ

=> ø1/ø2 = (q/Eₒ)/(q/Eₒ)

=> ø1/ø2 = 1/1

Ratio of flux is 1:1

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If our atmosphere had a uniform density of 1.25 kg/m3 all the way up to a border with empty space above, that border would be An
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Whit this equation we can find the value of H.

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10^5 N =  (10m/s^2)*(1.25 kg/m^3)*(1m^2*H)

(10^5 N)/(10 m/s^2) = (1.25 kg/m^3)*(1m^2*H)

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(10^4 kg)/( 1.25 kg/m^3) = 1m^2*H

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8,000 m = H

And we want this answer in km, knowing that 1,000m = 1km

8,000m = 8km = H

The border is 8km above sea level.

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