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miss Akunina [59]

4 years ago

15

A submarine sends a signal and receives an echo after 5 seconds. Calculate the speed of sound if distance of object from submari

ne
in 3625m.

2 answers:

quester [9]4 years ago

8 0

Distance of d object frm submarine = 3625m
time taken = 5/2

then speed = 3625/5/2. (speed = distance /time)
=> 1450m/s

seldon.

Reil [10]4 years ago

3 0

$speed = distance \div time$
Since the sound travels from the submarine to the object AND back, it actually travelled 3625x2=7250m.

$7250 \div 5 = 1450$
Speed of sound: 1450m/s

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A 235.0 g metal block absorbs 2.44 × 103 J of heat to raise its temperature by 35 K. What is the specific heat of the metal? Sho

andrew-mc [135]

When an object absorbs an amount of energy equal to Q, its temperature raises by $\Delta T$ following the formula
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In our problem, we have $Q=2.44 \cdot 10^3 J$ , $m=235.0 g$ and $\Delta T=35 K$ , so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal:
$C_s = \frac{Q}{m \Delta T}= \frac{2.44 \cdot 10^3 J}{(235.0 g)(35 K)}=0.297 J g^{-1} K^{-1}$

3 0

4 years ago

Suppose I have a spherical insulating shell with inner radius r and outer radius R. The shell has a uniformly distributed charge

a_sh-v [17]

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3Q / 4 pi (R^3 - r^3)

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4 0

4 years ago

Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl

ladessa [460]

Answer:

The frequency of these waves is $4.27\times10^{-2}\ Hz$

Explanation:

Given that,

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Distance = 8810 km

Time t = 8.67 hr

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Using formula of velocity

$v = \dfrac{D}{T}$

Where, D = distance

T = time

Put the value into the formula

$v =\dfrac{8810}{8.67}$

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Using formula of frequency

$v=n\lambda$

$n=\dfrac{v}{\lambda}$

Put the value into the formula

$n=\dfrac{1016}{6.6}$

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$n=0.0427\ Hz$

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8 0

4 years ago

A thin beam of light of wavelength 625 nm goes through a thin slit and falls on a screen 3.00 m past the slit. You observe that

AleksAgata [21]

Answer:

a = 2.275 10⁻⁴ m

Explanation:

This is a diffraction problem that is described by the equation

a sin θ = m λ

The first dark minimum occurs for m = 1

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tan θ = y / x

θ = tan⁻¹ y / x

Let's reduce the magnitudes to the SI system

y = 8.24 mm = 8.24 10⁻³ m

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θ = tan⁻¹ 8.24 10⁻³ / 3.00

θ = 0.002747 rad

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8 0

3 years ago

A vector is given in terms of its magnitude, v=8.7m/s and its direction, 256 degrees standard position. a) what is this vector i

Wittaler [7]

Answer:

Explanation:

Given

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Judging vector x and y component

It lies in third quadrant

4 0

3 years ago