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liubo4ka [24]
4 years ago
15

Explain why theories may be changed or replaced overnight time.

Physics
1 answer:
vlabodo [156]4 years ago
5 0
They may be changed because they may find evidence of some thing that will change their perspective on things.
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(II) You buy a 75-W lightbulb in Europe, where electricity is delivered at 240 V. If you use the bulb in the United States at 12
Elodia [21]

Answer:

Explanation:

You are looking for the resistance to start with

W = E * E/R

75 = 240 * 240 / R

75 * R = 240 * 240

R = 240 * 240 / 75

R = 57600 / 75

R = 768

Now let's see what happens when you try putting this into 110

W = E^2 / R

W = 120^2 / 768

W = 18.75

So the wattage is rated at 75. 18.75 is a far cry from that. I think they intend you to set up a ratio of

18.75 / 75 = 0.25

This is the long sure way of solving it. The quick way is to realize that the voltage is the only thing that is going to change. 120 * 120 / (240 * 240) = 1/2*1/2 = 1/4 = 0.25

4 0
3 years ago
8,000,000 kg of water are at the verge of dropping over Niagara Falls to the rocks 50.0 meters below. What is the change in grav
Gala2k [10]
Gravitational Potential Energy (GPE) = 9.8m/s² (rate of gravity) x 8,000,000kg of water x 50.0m

GPE = 3,294,000,000 Joules (J) which is also the change in GPE
5 0
4 years ago
ir temperature in a desert can reach 58.0°C (about 136°F). What is the speed of sound (in m/s) in air at that temperature?
Lerok [7]

Answer:

363m.s-1

Explanation:

6 0
3 years ago
Two particles are fixed to an x axis: particle 1 of charge −8.00 ✕ 10⁻⁷ C at x = 6.00 cm, and particle 2 of charge +8.00 ✕ 10⁻⁷
victus00 [196]

Answer:

0 N/C

Explanation:

Parameters given:

q_1 = -8.00 * 10^{-7} C

x_1 = 6.00 cm

q_2 = +8.00 * 10^{-7} C

x_2 = 21 cm

The distance between q_1 and q_2 is

21 - 6 = 15cm

Electric field is given as

E = \frac{kq}{r^2}

r = 15/2 = 7.5cm = 0.075m

The electric field at their midpoint due to q_1 is:

E = \frac{9 * 10^9 * -8.0 * 10^{-7}}{0.075^2}

E_1 = -1.28 * 10^6 N/C

The electric field at the midpoint due to q_2 is:

E = \frac{9 * 10^9 * 8.0 * 10^{-7}}{0.075^2}

E_2 = 1.28 * 10^6 N/C

The net electric field will be:

E = E_1 + E_2

E = -1.28 * 10^6 + 1.28 * 10^6

E = 0 N/C

7 0
4 years ago
The rms current in an ac current is 3.6<br> a. find the maximum current
LUCKY_DIMON [66]
A peak = A Rms x Sq root 2

Therefore 3.6 x sq root of 2
A peak = 5.09
7 0
4 years ago
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