KE at 16m/s
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Givens
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m = 575 kg
v = 16 m/s
Formula
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KE = 1/2 m* v^2
KE = 1/2 575 * 16^2
KE = 73600
Second Question
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m = 575
v = 32 m/s
KE = 1/2 mv^2
KE = 1/2 575 * 32^2
KE = 294400
Third Question
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Ke2 = KE1 * k where k is the number of times greater the second is than the first.
294400 = k * 73600
k = 294400 / 73600
k = 4 So the KE of the second condition is 4 times the first.
Answer:
14.68m/s
Explanation:
As per the question, the data provided is as follows
Mass = M = 0.148 kg
Height = h = 11 m
Initial velocity = U = 0 m/s
Final velocity = V
Gravitational force = F
Mass = M
Based on the above information, the speed that hit to the ground is
As we know that
Work to be done = Change in kinetic energy







= 14.68m/s
i dont know the answer of your question correctly
Umm I think the ocean floor but I don't think so