Question 1: C Question 2: B, Hope this Helps!
Answer:
Temperature of water leaving the radiator = 160°F
Explanation:
Heat released = (ṁcΔT)
Heat released = 20000 btu/hr = 5861.42 W
ṁ = mass flowrate = density × volumetric flow rate
Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³
ṁ = 1000 × 0.000126 = 0.126 kg/s
c = specific heat capacity for water = 4200 J/kg.K
H = ṁcΔT = 5861.42
ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C
And in change in temperature terms,
10°C= 18°F
11.08°C = 11.08 × 18/10 = 20°F
ΔT = T₁ - T₂
20 = 180 - T₂
T₂ = 160°F
Answer:
a)188.65m
b)154.35m
c)243.7m
Explanation:
Given data:
(a) The distance from the kicker to each of the 2 spectators is given by:
where,
v= speed of sound
=time taken for the sound waves to reach the ears
m
(b)
where,
v= speed of sound
=time taken for the sound waves to reach the ears
(c)As the angle b/w slight lines from the two spectators to the player is right angle,
hypotenuse=the distance b/w 2 spectators
and, the slight lines are the other 2 lines
<span>Organelles which are very important
in giving nutrients. During cellular respiration, the food molecules such as
glucose, are oxidized to carbon dioxide (CO2) and water (H2O) and trapped in
ATP (Adenosine triphosphate) form for further us of cell’s activities. ATP’s
are formed at mitochondria – the cell’s powerhouse. This type of organelle
takes and breaks nutrients absorbed by the cell and creates energy afterward.
The energy from ATP is then used by the body in kinetic activities like running
& walking or involuntary activities like breathing, blood circulation,
stimulus-responding, etc.</span>
Answer:
Explanation:
Given
Required
Determine the speed of the jet
The speed is calculated as:
Substitute 4800 km for Distance and 6hr for Time
<em>Hence, the speed of the commercial jet is 800km/hr</em>
