From the given information in the question, the correct option is Option 1: 14 cm.
A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:
PE =
k 
Where PE is the energy, k is the spring constant and x is extension.
i. Given that: PE = 10 J and x = 10 cm, then;
PE =
k 
10 =
k 
20 = 100k
k = 0.2 J/cm
ii. To determine how far the spring is needed to be stretched, given that PE = 20 J.
PE =
k 
20 =
(0.2) 
40 = 0.2 
= 200
x = 
= 14.1421
x = 14.14 cm
So that;
x is approximately 14.00 cm.
Thus, the spring need to be stretched to 14.00 cm to give the spring 20 J of elastic potential energy.
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Answer:
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The answer is : C ) air,water,and the tank glass.
-Hope this helps.
Answer:
Explanation:
Given
Resistor A has length 
and Resistor B has Length 
and Resistance is given by

Considering
and A to be constant thus
because 
(a)When they are connected in series
As the current in series is same and power is 
therefore
as R is greater for second resistor
(b)if they are connected in Parallel
In Parallel connection Voltage is same

resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2