Answer:
4.6 years
Explanation:
This is solved using Kepler's third law which says:

Where
T = Orbital period of the planet (in seconds)
a = Distance from the star (in meters)
G = Gravitational constant
M = Mass of the parent star (in kg)
From the information given



We put this into Kepler's law and get:

This when converted to years is 4.6 years.
Answer:
B) 2.7W
Explanation:
Converting Cal to Joule
1 cal = 4.186J
14 kcal = 14 x 1000 x 4.186
= 58604 J
Converting hour to seconds
6 hours = 6 x 60 x 60 seconds
= 21600 seconds
Power is the time rate of doing work.
Power = Work/Time
P = (58604) / (21600)
P = 2.7W
Answer:
Explanation:
Let the volume of air be V. at atmospheric pressure, that is 10⁵ Pa
At 20 m below surface pressure will be
atmospheric pressure + hdg
10⁵ + 20 x 9.8 x 1000 = 2.96 x 10⁵Pa
At this pressure volume V becomes V/ 2.96
This volume will last 1/2.96 times time that is 60/2.96 = 20.27 minutes.
Answer:
0.79 s
Explanation:
We have to calculate the employee acceleration, in order to know the minimum time. According to Newton's second law:

The frictional force is maximum since the employee has to apply a maximum force to spend the minimum time. In y axis the employee's acceleration is zero, so the net force is zero. Recall that 
Now, we find the acceleration:

Finally, using an uniformly accelerated motion formula, we can calculate the minimum time. The employee starts at rest, thus his initial speed is zero:
