The position vector can be
transcribed as:
A<span> = 6 i + y j
</span>
i <span>points in the x-direction and j points
in the y-direction.</span>
The magnitude of the
vector is its dot product with itself:
<span>|A|2 = A·A</span>
<span>102 = (6 i +
y j)•(6 i+ y j)
Note that i•j = 0, and i•i = j•j =
1 </span>
<span>100 = 36 + y2
</span>
<span>64 = y2</span>
<span>get the square root of 64 = 8</span>
<span>The vertical component of the vector is 8 cm.</span>
Answer:
the hydrogen filled balloon is denser than the air filled balloon
There are three forces acting on the book.
1. Force due to gravity
2. Force exerted downward by the hamster
3. Normal Force in reaction to the downward forces
Since the book is not moving, the net force is zero. The summation of all forces must be zero. Then we could find the normal force which is unknown (denoted as x).
∑F = -(4 kg)(9.81 m/s2) - 3 N + x =0
∑F = -39.24 N - 3N + x =0
x = 42 N
Therefore, the normal force is 42 N.
The process by which the heat energy is transmitted between the atoms or molecules is known as conduction.
Explanation:
Conduction is the transfer of heat through the material that are caused by temperature gradient with the material ends in heat flux. The heat transfer done by movement and mixing of a fluid is known as convection.
If a fluid is taken and it is kept as stationary. If there is a temperature gradient across that fluid, there would be transfer of heat that occurs in the fluid. It is negligible when compared to convective heat transfer.
Because of the heat transfer from solid to solid, density of liquid changes and start to move in upward direction due to low density. This type of motion is known as convection currents.
Answer:
Explanation:
Total Resistance, Rt = (0.35 + 0.002 + 5200 + 0.5 + 0.008 + 1100) = 6300 ohms
a) Capacity of transformer, Pt = 150KVA = 150,000 W
Input Voltage, Vp = 2.8 KV = 2800 V
Current, Ip = 150000/2800 = 53.57 A
Input impedance, Zp = Vp/Ip = 2800/5357 = 52.27 ohms
b) i) Input current = 53.57 A
ii) Voltage, V = Ip * Rt = 53.57 X 6300 = 337.5 KV
iii) Power, P = I² * Rt = (53.57)² X 6300 = 18.08 MW
iv) Power factor = 0.83
