Compare the forces in a small nucleus to the forces in a large nucleus
1 answer:
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Answer:
The moment is -78.4 N-m (clockwise).
Explanation:
Given:
Mass of the object (m) = 20 kg
Distance of the object from the knee joint (d) = 0.4 m
Weight of leg is not considered.
Acceleration due to gravity (g) = 9.8 m/s²
Now, weight of the object is equal to the product of its mass and acceleration due to gravity. So,
Weight = Mass × Acceleration due to gravity
=
We know that, moment of a force about a point is defined as the product of force applied and the perpendicular distance between the point and the line of application of force.
Moment of the given weight about the knee joint is given as:
Moment about knee joint = Weight × Distance from knee joint to weight
Moment about knee joint = 196 × 0.4 = 78.4 Nm
Now, from the diagram below, we can observe that, the weight acts vertically down and thus the sense of rotation about the knee joint at point O is clockwise. So, moment is negative.
Therefore, the moment is -78.4 N-m (clockwise).
The value of resistance will be 60 ohms. Resistance is the opposition force offered to the flow of electric current. The ratio of the voltage to the electric current passing through the wire.
<h3>What is a resistor?</h3>A resistor is a two-terminal passive electrical component that acts as a circuit element by implementing electrical resistance.
Resistors are used to limit current flow, alter signal levels, divide voltages, bias active devices, and complete transmission lines in electronic circuits.
The given data in the problem is;
V is the voltage = 3. 0 V
I is value of electric current= 0. 05 A
R is the resistance=?
According to ohm's law, the potential difference between the two ends of the conductor is equal to the product of electric current and the resistance generated.
So from the ohm law;
V= IR
Hence the value of resistance will be 60 ohms.
To learn more about the resistor refer to the link;