Constant: A value that doesn't change. Instead, it's a fixed value.
Variable: A symbol (usually a letter) standing in for an unknown numerical value in an equation.
Term: Either a single number or variable, or numbers and variables multiplied together. (Terms are separated by + or − signs, or sometimes by divide.)
Like Terms: Terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are "like" each other.
Coefficient: A number used to multiply a variable.
Answer:
28
Step-by-step explanation:
Plug in the corresponding numbers to the corresponding variables. Note that:
m = 7
r = 8
t = 2
mr/t = (7 * 8)/2
(7 * (8/2)) = 7 * 4 = 28
28 is your answer.
~
Answer:
0.03
Step-by-step explanation:
There are two 0s so it is 0.03

We want to find
such that
. This means



Integrating both sides of the latter equation with respect to
tells us

and differentiating with respect to
gives

Integrating both sides with respect to
gives

Then

and differentiating both sides with respect to
gives

So the scalar potential function is

By the fundamental theorem of calculus, the work done by
along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it
) in part (a) is

and
does the same amount of work over both of the other paths.
In part (b), I don't know what is meant by "df/dt for F"...
In part (c), you're asked to find the work over the 2 parts (call them
and
) of the given path. Using the fundamental theorem makes this trivial:


Answer:
<em>44, definition below</em>
Step-by-step explanation:
- An outlier is a number that is much larger or smaller than the general populous of numbers. For example, if there was a dot plot with dots clustered at 2, 3, and 5, but there was one or two dots around 10, then 10 would be considered an outlier.
- I would consider 44 to be an outlier in the number set.
If I am incorrect in my reasoning, please let me know so that I can plan better for my future answers. Have an amazing day.