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Korolek [52]
4 years ago
9

As the building collapses, the volume of air inside the building decreases, while the mass of the air stays the same. This means

that the _____ of the air inside the building will increase
Chemistry
2 answers:
Anettt [7]4 years ago
8 0
I think the answer to your question is Density
erastovalidia [21]4 years ago
5 0

Answer is: density.

Density is a measure of mass per unit of volume: d(air) = m(air)/V(air).

d - density of air.

m - mass of air.

V - volume of air.

For example, if we take:

m(air) = 1 kg.

V₁(air) = 100 dm³.

d₁(air) = 1 kg/100 dm³.

d₁(air) = 0.01 kg/dm³; density before the building collapse.

V₂(air) = 50 dm³.

d₂(air) = 1 kg/50 dm³.

d₂(air) = 0.02kg/dm³; density after the building collapse.

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Answer:

This question has no options but it can be answered based on the understanding of the function of ribosomes.

The effect is the deficiency of proteins in the cell.

Explanation:

Ribosomes are one of the most important cellular organelles found in living organisms. Infact, they are so important that they are found in both the prokaryotic and eukaryotic cell. Ribosome functions in PROTEIN SYNTHESIS as they are the site where the mRNA encoding protein building blocks (amino acids) undergo their translational process.

According to this question, an analyzed cell is found to be missing most of its ribosomes. This means that the function performed by the missing organelle, which is SYNTHESIS OF PROTEINS, will be lacking. Hence, that particular cell will be PROTEIN-DEFICIENT.

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Explain why potassium atom would not bond with a calcium atom.
schepotkina [342]

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Explanation:

4 0
2 years ago
Help please just #17
defon
So you see the triangle with the letters, look at what you're given. you have mass and volume solving for density. So you take the mass and divide it by the volume. 15.2/15.5 which your answer is 0.98 or 1.0 that's your density.
4 0
3 years ago
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Cobalt-59 is a stable isotope and cobalt-60 is an unstable or radioactive isotope. These two isotopes differ in the number of -
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7 0
4 years ago
1) Aluminum sulphate can be made by the following reaction: 2AlCl3(aq) + 3H2SO4(aq) Al2(SO4)3(aq) + 6 HCl(aq) It is quite solubl
kolezko [41]

Answer:

88.9%

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2AlCl3(aq) + 3H2SO4(aq) —> Al2(SO4)3(aq) + 6HCl(aq)

Step 2:

Determination of the masses of AlCl3 and H2SO4 that reacted and the mass of Al2(SO4)3 produced from the balanced equation.

Molar mass of AlCl3 = 27 + (35.5x3) = 133.5g/mol

Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g

Molar mass of H2SO4 = (2x1) + 32 + (16x4) = 98g/mol

Mass of H2SO4 from the balanced equation = 3 x 98 = 294g

Molar mass of Al2(SO4)3 = (27x2) + 3[32 + (16x4)]

= 54 + 3[32 + 64]

= 54 + 3[96] = 342g/mol

Mass of Al2(SO4)3 from the balanced equation = 1 x 342 = 342g

Summary:

From the balanced equation above,

267g of AlCl3 reacted with 294g of H2SO4 to produce 342g of Al2(SO4)3.

Step 3:

Determination of the limiting reactant. This is illustrated below:

From the balanced equation above,

267g of AlCl3 reacted with 294g of H2SO4.

Therefore, 25g of AlCl3 will react with = (25 x 294)/267 = 27.53g of H2SO4.

From the calculations made above, we see that only 27.53g out 30g of H2SO4 given were needed to react completely with 25g of AlCl3.

Therefore, AlCl3 is the limiting reactant and H2SO4 is the excess.

Step 4:

Determination of the theoretical yield of Al2(SO4)3.

In this case we shall be using the limiting reactant because it will produce the maximum yield of Al2(SO4)3 since all of it is used up in the reaction.

The limiting reactant is AlCl3 and the theoretical yield of Al2(SO4)3 can be obtained as follow:

From the balanced equation above,

267g of AlCl3 reacted to produce 342g of Al2(SO4)3.

Therefore, 25g of AlCl3 will react to produce = (25 x 342) /267 = 32.02g of Al2(SO4)3.

Therefore, the theoretical yield of Al2(SO4)3 is 32.02g

Step 5:

Determination of the percentage yield of Al2(SO4)3.

This can be obtained as follow:

Actual yield of Al2(SO4)3 = 28.46g

Theoretical yield of Al2(SO4)3 = 32.02g

Percentage yield of Al2(SO4)3 =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 28.46/32.02 x 100

Percentage yield = 88.9%

Therefore, the percentage yield of Al2(SO4)3 is 88.9%

3 0
4 years ago
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