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kvasek [131]
2 years ago
9

Layers of sediment forming at the bottom of the ocean

Chemistry
2 answers:
Kruka [31]2 years ago
7 0

Answer: The Process is Deposition

Explanation:

elena-14-01-66 [18.8K]2 years ago
7 0

Answer:

Deposition

Explanation:The accumulation or laying down of matter by a natural process, as in the laying down of sediments in streams or rivers.

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Elements in an element group have similar
svetlana [45]

Answer:

chemical properties and the same number of valence electrons

8 0
3 years ago
Os etapas que devem sem compridas para obter separadamente os componentes (a as substâncias ) de uma mistura de água ,sal e arei
SashulF [63]

Answer:

The steps that must be long to obtain separately the components (to the substances) of a mixture of water, salt and sand, are respectively: A) filtration and siphoning B) decanting and siphoning C) simple filtration and distillation D) collection and decantation.

Simple filtration and Siphoning is the method. When an insoluble solid is present in a liquid. Filtration is the ideal method of separation,The sand is filtered by the filtered paper as water is allowed to pass through the filter paper into a beaker where the funnel which hold the filter paper emptied into.

Water molecules is Siphoned, pull by force of gravity through the sand, past  the filter paper to emerge as clean in the beaker below.

4 0
4 years ago
Which of the following is an example of a physical change?
MatroZZZ [7]

Answer:

A

Explanation:

because you can turn the melted iron back to the solid it was before

5 0
3 years ago
Is cyclopentane an isomer of pentane? Explain.
Georgia [21]
Cyclopentane is NOT an isomer of pentane.

Isomers must have the same molecular formula.

The molecular formula of pentane is C₅H₁₂, while the molecular formula of cyclopentane is C₅H₁₀.

The two molecules cannot be isomers.
8 0
4 years ago
When metallic sodium is dissolved in liquid sodium chloride, electrons are released into the liquid. These dissolved electrons a
qaws [65]

Answer:

The edge of the length is \mathbf{L = 8.54 \times 10^{-10} \ m}

Explanation:

From the given information:

The associated energy for a particle in three - dimensional box can be expressed as:

E_n = \dfrac{h^2}{8mL^2}(n_x^2+n_y^2+n_z^2)

here;

h = planck's constant = 6.626 \times 10^{-34} \ Js

n_i = the quantum no in a specified direction

m = mass (of particle)

L = length of the box

At the ground state n_x = n_y = n_z=1

The energy at the ground state can be calculated by using the formula:

E_1 =\dfrac{3h^2}{8mL^2}

At first excited energy level, one of the quantum values will be 2 and the others will be 1.

Thus, the first excited energy will be: 2,1,1

∴

E_2 =\dfrac{(2^2+1^2+1^2)h^2}{8mL^2}

E_2 =\dfrac{(4+1+1)h^2}{8mL^2}

E_2 =\dfrac{(6)h^2}{8mL^2}

The transition energy needed to move from the ground to the excited state is:

\Delta E= E_2 - E_1

\Delta E= \dfrac{6h^2}{8mL^2}-  \dfrac{3h^2}{8mL^2}

\Delta E= \dfrac{3h^2}{8mL^2}} ----- (1)

Recall that:

the  wavelength identified with the electronic transition is: 800 nm

800 nm = 8.0  × 10⁻⁷ m

However, the energy-related with the electronic transition is:

\Delta E =\dfrac{hc}{\lambda}

\Delta E =\dfrac{6.626 \times 10^{-34} \times 2.99 \times 10^8}{8.0 \times 10^{-7} }

\Delta E =2.48 \times 10^{-19}  \ J

Replacing the value of \Delta E in (1); then:

2.48 \times 10^{-19}= \dfrac{3h^2}{8mL^2}}

Making the edge length L the subject of the formula; we have:

L = \sqrt{\dfrac{3h^2}{8m \times2.48 \times 10^{-19}} }

L = \sqrt{\dfrac{3\times (6.626 \times 10^{-34})^2}{8(9.1 \times 10^{-31} ) \times2.48 \times 10^{-19}} }

\mathbf{L = 8.54 \times 10^{-10} \ m}

Thus, the edge of the length is \mathbf{L = 8.54 \times 10^{-10} \ m}

5 0
3 years ago
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