Answer:
a) 2.4 mm
b) 1.2 mm
c) 1.2 mm
Explanation:
To find the widths of the maxima you use the diffraction condition for destructive interference, given by the following formula:

a: width of the slit
λ: wavelength
m: order of the minimum
for little angles you have:

y: height of the mth minimum
a) the width of the central maximum is 2*y for m=1:

b) the width of first maximum is y2-y1:
![w=y_2-y_1=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[2-1]=1.2mm](https://tex.z-dn.net/?f=w%3Dy_2-y_1%3D%5Cfrac%7B%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%5B2-1%5D%3D1.2mm)
c) and for the second maximum:
![w=y_3-y_2=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[3-2]=1.2mm](https://tex.z-dn.net/?f=w%3Dy_3-y_2%3D%5Cfrac%7B%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%5B3-2%5D%3D1.2mm)
Answer:

Explanation:
The total energy of the satellite when it is still in orbit is given by the formula

where
G is the gravitational constant
m = 525 kg is the mass of the satellite
is the Earth's mass
r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:

So the initial total energy is

When the satellite hits the ground, it is now on Earth's surface, so

so its gravitational potential energy is

And since it hits the ground with speed

it also has kinetic energy:

So the total energy when the satellite hits the ground is

So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:

Answer:
It's a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal bars. It can also be described as the sharing of free electrons among a structure of positively charged ions
Since kinetic energy is a form of energy using the equation KE=¹/₂mv², the units of measurement is in Joules (J). Therefore, the tennis ball had more kinetic energy than the baseball since velocity is a larger factor than the mass is when determining kinetic energy.
44.64m
Explanation:
Given parameters:
Mass of the car = 1500kg
Initial velocity = 25m/s
Frictional force = 10500N
Unknown:
Distance moved by the car after brake is applied = ?
Solution:
The frictional force is a force that opposes motion of a body.
To solve this problem, we need to find the acceleration of the car. After this, we apply the appropriate motion equation to solve the problem.
-Frictional force = m x a
the negative sign is because the frictional force is in the opposite direction
m is the mass of the car
a is the acceleration of the car
a =
=
= -7m/s²
Now using;
V² = U² + 2as
V is the final velocity
U is the initial velocity
a is the acceleration
s is the distance moved
0² = 25² + 2 x 7 x s
0 = 625 - 14s
-625 = -14s
s = 44.64m
learn more:
Velocity problems brainly.com/question/10932946
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