Because,
In left image pin is not touch to the wire.
In right image pin is touch to the wire.
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Answer:
k = 1 700.7 N/m
v0 = 9.8 m/s^2
Explanation:
Hello!
We can answer this question using conservation of energy.
The potential energy of the spring (PS) will transform to kinetic energy (KE) of the ball, and eventually, when the velocity of the ball is zero, all that energy will be potential gravitational (PG) energy.
When the kinetic energy of the ball is zero, that is, when it has reached its maximum heigh, all the potential energy of the spring will be equal to the potential energy of the gravitational field.
PS = (1/2) k x^2 <em>where x is the compresion or elongation of the spring</em>
PG = mgh
a)
Since energy must be conserved and we are neglecting any energy loss:
PS = PG
Solving for k
k = (2mgh)/(x^2) = ( 2 * 1.7 * 9.81 * 4.9 Nm)/(0.31^2 m^2)
k = 1 700.7 N/m
b)
Since the potential energy of the spring transfors to kinetic energy of the ball we have that:
PS = KE
that is:
(1/2) k x^2 = (1/2) m v0^2
Solving for v0
v0 = x √(k/m) = (0.31 m ) √( 1 700.7 N/m / 1.7kg)
v0 = 9.8 m/s^2
Answer:
F) The acceleration due to gravity is g/27
Explanation:
According to Newton gravitational law, the gravitational acceleration is directly proportional to the planet mass and inversely proportional to the square of distance.
Since our new planet has a mass of one-third of Earth's and radius 3 times of Earth's. This means the new planet is lighter and further away from the distance. This means g is first reduced by 3 due to smaller mass and then reduced by 9 due to square of 3 times the distance.
The gravitational acceleration on this new planet must be
So F) is the correct answer
Answer:
a)30.67 m/s
b)348,12 Hz
c)32,34 m/s
d)289,69 Hz
Explanation:
a)
To convert 69 mph to m/s we have:
b)
For a resting receiver and an approaching source we have the following Doppler formula:
where 
is the source, and c is the speed of sound, f the perceived frequency and 
the frequency as perceived by the source. Plugging all the relevant values we get:
c)
Using the same formula as above and solving for we have:
d)
Now we have another Doppler formula for a source that is moving away from the receiver:
